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SRS Stand 10685 pair #381718467
details
property
value
status
complete
benchmark
02-oppelt08.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n035.star.cs.uiowa.edu
space
Mixed_SRS
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
15.4949760437 seconds
cpu usage
58.242145677
max memory
4.479635456E9
stage attributes
key
value
output-size
1730
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 3397 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: c(b(x1)) -> b(a(x1)) a(c(x1)) -> a(b(c(x1))) b(b(x1)) -> b(c(x1)) c(a(x1)) -> c(c(c(x1))) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "b (c)^k+1 b c -> b (c)^2k+3 b c" b (c)^k+1 b c -> b (c)^2k+3 b c by Equivalent"b (c)^k+1 b c -> b (c c)^k+1 c b c by Overlapping Derivationstructures"b (c)^k+1 b c -> b c (a)^k+1 b c by Equivalent"b (c)^k+1 b c -> b c (a)^k a b c by Overlap u with r (ol3)"b (c)^k+1 b -> b c (a)^k a by Operation expand"b (c)^k+1 b -> b c (a)^k+1 by Overlap u with l (ol4)"(c)^k+1 b -> b (a)^k+1 by Operation lift"(c)^k b -> b (a)^k by Selfoverlapping OC am1"c b -> b a by original rule (OC 1)""""b b -> b c by original rule (OC 1)""""a c -> a b c by original rule (OC 1)""""c (a)^k+1 -> (c c)^k+1 c by Operation lift"c (a)^k -> (c c)^k c by Selfoverlapping OC am2"c a -> c c c by original rule (OC 1)"""" ---------------------------------------- (2) NO
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