details

property	value
status	complete
benchmark	dup12.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n192.star.cs.uiowa.edu
space	Trafo_06

run statistics

property	value
solver	ttt2-1.17+nonreach
configuration	ttt2-1.17+nonreach
runtime (wallclock)	4.49749803543 seconds
cpu usage	16.568865823
max memory	1.014992896E9

stage attributes

key	value
output-size	4583
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: b(b(d(d(b(b(x1)))))) -> c(c(d(d(b(b(x1)))))) b(b(a(a(c(c(x1)))))) -> b(b(c(c(x1)))) a(a(d(d(x1)))) -> d(d(c(c(x1)))) b(b(b(b(b(b(x1)))))) -> a(a(b(b(c(c(x1)))))) d(d(c(c(x1)))) -> b(b(d(d(x1)))) d(d(c(c(x1)))) -> d(d(b(b(d(d(x1)))))) d(d(a(a(c(c(x1)))))) -> b(b(b(b(x1)))) Proof: Matrix Interpretation Processor: dim=1 interpretation: [a](x0) = x0 + 1, [c](x0) = x0 + 1, [d](x0) = x0, [b](x0) = x0 + 1 orientation: b(b(d(d(b(b(x1)))))) = x1 + 4 >= x1 + 4 = c(c(d(d(b(b(x1)))))) b(b(a(a(c(c(x1)))))) = x1 + 6 >= x1 + 4 = b(b(c(c(x1)))) a(a(d(d(x1)))) = x1 + 2 >= x1 + 2 = d(d(c(c(x1)))) b(b(b(b(b(b(x1)))))) = x1 + 6 >= x1 + 6 = a(a(b(b(c(c(x1)))))) d(d(c(c(x1)))) = x1 + 2 >= x1 + 2 = b(b(d(d(x1)))) d(d(c(c(x1)))) = x1 + 2 >= x1 + 2 = d(d(b(b(d(d(x1)))))) d(d(a(a(c(c(x1)))))) = x1 + 4 >= x1 + 4 = b(b(b(b(x1)))) problem: b(b(d(d(b(b(x1)))))) -> c(c(d(d(b(b(x1)))))) a(a(d(d(x1)))) -> d(d(c(c(x1)))) b(b(b(b(b(b(x1)))))) -> a(a(b(b(c(c(x1)))))) d(d(c(c(x1)))) -> b(b(d(d(x1)))) d(d(c(c(x1)))) -> d(d(b(b(d(d(x1)))))) d(d(a(a(c(c(x1)))))) -> b(b(b(b(x1)))) Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [a](x0) = [0 0 1]x0 [0 1 0] , [1 0 0] [c](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [0] [d](x0) = [0 1 0]x0 + [1] [0 0 0] [0], [1 0 0] [b](x0) = [0 0 0]x0 [0 0 0] orientation: [1 0 0] [1 0 0] b(b(d(d(b(b(x1)))))) = [0 0 0]x1 >= [0 0 0]x1 = c(c(d(d(b(b(x1)))))) [0 0 0] [0 0 0] [1 1 0] [2] [1 0 0] [0] a(a(d(d(x1)))) = [0 1 0]x1 + [2] >= [0 0 0]x1 + [2] = d(d(c(c(x1)))) [0 0 0] [0] [0 0 0] [0] [1 0 0] [1 0 0] b(b(b(b(b(b(x1)))))) = [0 0 0]x1 >= [0 0 0]x1 = a(a(b(b(c(c(x1)))))) [0 0 0] [0 0 0] [1 0 0] [0] [1 0 0] d(d(c(c(x1)))) = [0 0 0]x1 + [2] >= [0 0 0]x1 = b(b(d(d(x1)))) [0 0 0] [0] [0 0 0] [1 0 0] [0] [1 0 0] [0] d(d(c(c(x1)))) = [0 0 0]x1 + [2] >= [0 0 0]x1 + [2] = d(d(b(b(d(d(x1)))))) [0 0 0] [0] [0 0 0] [0] [1 0 0] [0] [1 0 0] d(d(a(a(c(c(x1)))))) = [0 0 0]x1 + [2] >= [0 0 0]x1 = b(b(b(b(x1)))) [0 0 0] [0] [0 0 0] problem: b(b(d(d(b(b(x1)))))) -> c(c(d(d(b(b(x1)))))) b(b(b(b(b(b(x1)))))) -> a(a(b(b(c(c(x1)))))) d(d(c(c(x1)))) -> b(b(d(d(x1)))) d(d(c(c(x1)))) -> d(d(b(b(d(d(x1)))))) d(d(a(a(c(c(x1)))))) -> b(b(b(b(x1)))) String Reversal Processor: b(b(d(d(b(b(x1)))))) -> b(b(d(d(c(c(x1)))))) b(b(b(b(b(b(x1)))))) -> c(c(b(b(a(a(x1)))))) popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to SRS Stand 10685