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SRS Stand 10685 pair #381718674
details
property
value
status
complete
benchmark
size-12-alpha-3-num-560.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n021.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
22.0900621414 seconds
cpu usage
86.845410272
max memory
7.03066112E8
stage attributes
key
value
output-size
2132
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: a(b(x1)) -> x1 a(c(x1)) -> c(c(x1)) b(c(x1)) -> a(a(b(b(x1)))) Proof: DP Processor: DPs: b#(c(x1)) -> b#(x1) b#(c(x1)) -> b#(b(x1)) b#(c(x1)) -> a#(b(b(x1))) b#(c(x1)) -> a#(a(b(b(x1)))) TRS: a(b(x1)) -> x1 a(c(x1)) -> c(c(x1)) b(c(x1)) -> a(a(b(b(x1)))) TDG Processor: DPs: b#(c(x1)) -> b#(x1) b#(c(x1)) -> b#(b(x1)) b#(c(x1)) -> a#(b(b(x1))) b#(c(x1)) -> a#(a(b(b(x1)))) TRS: a(b(x1)) -> x1 a(c(x1)) -> c(c(x1)) b(c(x1)) -> a(a(b(b(x1)))) graph: b#(c(x1)) -> b#(b(x1)) -> b#(c(x1)) -> a#(a(b(b(x1)))) b#(c(x1)) -> b#(b(x1)) -> b#(c(x1)) -> a#(b(b(x1))) b#(c(x1)) -> b#(b(x1)) -> b#(c(x1)) -> b#(b(x1)) b#(c(x1)) -> b#(b(x1)) -> b#(c(x1)) -> b#(x1) b#(c(x1)) -> b#(x1) -> b#(c(x1)) -> a#(a(b(b(x1)))) b#(c(x1)) -> b#(x1) -> b#(c(x1)) -> a#(b(b(x1))) b#(c(x1)) -> b#(x1) -> b#(c(x1)) -> b#(b(x1)) b#(c(x1)) -> b#(x1) -> b#(c(x1)) -> b#(x1) SCC Processor: #sccs: 1 #rules: 2 #arcs: 8/16 DPs: b#(c(x1)) -> b#(b(x1)) b#(c(x1)) -> b#(x1) TRS: a(b(x1)) -> x1 a(c(x1)) -> c(c(x1)) b(c(x1)) -> a(a(b(b(x1)))) Arctic Interpretation Processor: dimension: 1 usable rules: a(b(x1)) -> x1 a(c(x1)) -> c(c(x1)) b(c(x1)) -> a(a(b(b(x1)))) interpretation: [b#](x0) = x0 + 2, [c](x0) = 1x0 + 12, [a](x0) = 1x0 + 0, [b](x0) = -1x0 + 0 orientation: b#(c(x1)) = 1x1 + 12 >= -1x1 + 2 = b#(b(x1)) b#(c(x1)) = 1x1 + 12 >= x1 + 2 = b#(x1) a(b(x1)) = x1 + 1 >= x1 = x1 a(c(x1)) = 2x1 + 13 >= 2x1 + 13 = c(c(x1)) b(c(x1)) = x1 + 11 >= x1 + 2 = a(a(b(b(x1)))) problem: DPs: TRS: a(b(x1)) -> x1 a(c(x1)) -> c(c(x1)) b(c(x1)) -> a(a(b(b(x1)))) Qed
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