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SRS Stand 10685 pair #381718741
details
property
value
status
complete
benchmark
loop2.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n029.star.cs.uiowa.edu
space
Zantema_06
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.59931397438 seconds
cpu usage
3.455742176
max memory
1.87170816E8
stage attributes
key
value
output-size
1512
starexec-result
NO
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 0 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: b(b(b(x1))) -> a(a(x1)) a(a(x1)) -> b(a(b(x1))) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "a a b b a b b a -> b a a b b a b b a b" a a b b a b b a -> b a a b b a b b a b by OverlapClosure OC 2"a a b b a b b -> b a a b b a b a by OverlapClosure OC 2"a a -> b a b by original rule (OC 1)""b b b a b b -> a b b a b a by OverlapClosure OC 2"b b b -> a a by original rule (OC 1)""a a b b -> b b a b a by OverlapClosure OC 3"a a b b -> b a a a by OverlapClosure OC 2"a a -> b a b by original rule (OC 1)""b b b -> a a by original rule (OC 1)"""a a -> b a b by original rule (OC 1)"""""a a -> b a b by original rule (OC 1)" ---------------------------------------- (2) NO
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