details

property	value
status	complete
benchmark	un09.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n042.star.cs.uiowa.edu
space	Trafo_06

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	16.8398599625 seconds
cpu usage	62.874805748
max memory	5.68559616E9

stage attributes

key	value
output-size	5822
starexec-result	YES

output

/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 21 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 0 ms] (4) QDP (5) QDPOrderProof [EQUIVALENT, 2364 ms] (6) QDP (7) QDPOrderProof [EQUIVALENT, 37 ms] (8) QDP (9) DependencyGraphProof [EQUIVALENT, 0 ms] (10) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: b(b(b(a(b(x1))))) -> b(a(b(b(a(b(x1)))))) b(a(b(b(x1)))) -> b(b(a(b(a(b(x1)))))) b(a(b(a(a(b(b(x1))))))) -> b(a(a(b(a(a(b(b(b(a(b(x1))))))))))) Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: B(b(b(a(b(x1))))) -> B(a(b(b(a(b(x1)))))) B(a(b(b(x1)))) -> B(b(a(b(a(b(x1)))))) B(a(b(b(x1)))) -> B(a(b(a(b(x1))))) B(a(b(b(x1)))) -> B(a(b(x1))) B(a(b(a(a(b(b(x1))))))) -> B(a(a(b(a(a(b(b(b(a(b(x1))))))))))) B(a(b(a(a(b(b(x1))))))) -> B(a(a(b(b(b(a(b(x1)))))))) B(a(b(a(a(b(b(x1))))))) -> B(b(b(a(b(x1))))) B(a(b(a(a(b(b(x1))))))) -> B(b(a(b(x1)))) B(a(b(a(a(b(b(x1))))))) -> B(a(b(x1))) The TRS R consists of the following rules: b(b(b(a(b(x1))))) -> b(a(b(b(a(b(x1)))))) b(a(b(b(x1)))) -> b(b(a(b(a(b(x1)))))) b(a(b(a(a(b(b(x1))))))) -> b(a(a(b(a(a(b(b(b(a(b(x1))))))))))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (3) DependencyGraphProof (EQUIVALENT) The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 2 less nodes. ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: B(a(b(b(x1)))) -> B(b(a(b(a(b(x1)))))) B(b(b(a(b(x1))))) -> B(a(b(b(a(b(x1)))))) B(a(b(b(x1)))) -> B(a(b(a(b(x1))))) B(a(b(b(x1)))) -> B(a(b(x1))) B(a(b(a(a(b(b(x1))))))) -> B(b(b(a(b(x1))))) B(a(b(a(a(b(b(x1))))))) -> B(b(a(b(x1)))) B(a(b(a(a(b(b(x1))))))) -> B(a(b(x1))) The TRS R consists of the following rules: b(b(b(a(b(x1))))) -> b(a(b(b(a(b(x1)))))) b(a(b(b(x1)))) -> b(b(a(b(a(b(x1)))))) b(a(b(a(a(b(b(x1))))))) -> b(a(a(b(a(a(b(b(b(a(b(x1))))))))))) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (5) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. popout

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