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SRS Stand 10685 pair #381718861
details
property
value
status
complete
benchmark
z082.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n035.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
2.34660506248 seconds
cpu usage
8.106746135
max memory
8.0746496E8
stage attributes
key
value
output-size
3547
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: a(c(a(x1))) -> c(a(c(x1))) a(a(b(x1))) -> a(d(b(x1))) a(b(x1)) -> b(a(a(x1))) d(d(x1)) -> a(d(b(x1))) b(b(x1)) -> b(c(x1)) a(d(c(x1))) -> c(a(x1)) b(c(x1)) -> a(a(a(x1))) Proof: String Reversal Processor: a(c(a(x1))) -> c(a(c(x1))) b(a(a(x1))) -> b(d(a(x1))) b(a(x1)) -> a(a(b(x1))) d(d(x1)) -> b(d(a(x1))) b(b(x1)) -> c(b(x1)) c(d(a(x1))) -> a(c(x1)) c(b(x1)) -> a(a(a(x1))) Matrix Interpretation Processor: dim=2 interpretation: [1 2] [0] [d](x0) = [0 0]x0 + [3], [1 0] [0] [b](x0) = [0 0]x0 + [3], [1 0] [c](x0) = [0 0]x0, [1 0] [a](x0) = [0 0]x0 orientation: [1 0] [1 0] a(c(a(x1))) = [0 0]x1 >= [0 0]x1 = c(a(c(x1))) [1 0] [0] [1 0] [0] b(a(a(x1))) = [0 0]x1 + [3] >= [0 0]x1 + [3] = b(d(a(x1))) [1 0] [0] [1 0] b(a(x1)) = [0 0]x1 + [3] >= [0 0]x1 = a(a(b(x1))) [1 2] [6] [1 0] [0] d(d(x1)) = [0 0]x1 + [3] >= [0 0]x1 + [3] = b(d(a(x1))) [1 0] [0] [1 0] b(b(x1)) = [0 0]x1 + [3] >= [0 0]x1 = c(b(x1)) [1 0] [1 0] c(d(a(x1))) = [0 0]x1 >= [0 0]x1 = a(c(x1)) [1 0] [1 0] c(b(x1)) = [0 0]x1 >= [0 0]x1 = a(a(a(x1))) problem: a(c(a(x1))) -> c(a(c(x1))) b(a(a(x1))) -> b(d(a(x1))) b(a(x1)) -> a(a(b(x1))) b(b(x1)) -> c(b(x1)) c(d(a(x1))) -> a(c(x1)) c(b(x1)) -> a(a(a(x1))) String Reversal Processor: a(c(a(x1))) -> c(a(c(x1))) a(a(b(x1))) -> a(d(b(x1))) a(b(x1)) -> b(a(a(x1))) b(b(x1)) -> b(c(x1)) a(d(c(x1))) -> c(a(x1)) b(c(x1)) -> a(a(a(x1))) Matrix Interpretation Processor: dim=1 interpretation: [d](x0) = x0, [b](x0) = x0 + 1, [c](x0) = x0, [a](x0) = x0 orientation: a(c(a(x1))) = x1 >= x1 = c(a(c(x1))) a(a(b(x1))) = x1 + 1 >= x1 + 1 = a(d(b(x1))) a(b(x1)) = x1 + 1 >= x1 + 1 = b(a(a(x1))) b(b(x1)) = x1 + 2 >= x1 + 1 = b(c(x1)) a(d(c(x1))) = x1 >= x1 = c(a(x1)) b(c(x1)) = x1 + 1 >= x1 = a(a(a(x1))) problem: a(c(a(x1))) -> c(a(c(x1))) a(a(b(x1))) -> a(d(b(x1)))
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