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SRS Stand 10685 pair #381719011
details
property
value
status
complete
benchmark
z005.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n085.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
muterm 5.18
configuration
default
runtime (wallclock)
58.0570189953 seconds
cpu usage
57.313204696
max memory
8.6593536E7
stage attributes
key
value
output-size
6239
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x1) (RULES a(a(x1)) -> a(b(c(a(x1)))) a(c(b(x1))) -> b(a(b(a(x1)))) b(x1) -> c(a(c(x1))) ) Problem 1: Dependency Pairs Processor: -> Pairs: A(a(x1)) -> A(b(c(a(x1)))) A(a(x1)) -> B(c(a(x1))) A(c(b(x1))) -> A(b(a(x1))) A(c(b(x1))) -> A(x1) A(c(b(x1))) -> B(a(b(a(x1)))) A(c(b(x1))) -> B(a(x1)) B(x1) -> A(c(x1)) -> Rules: a(a(x1)) -> a(b(c(a(x1)))) a(c(b(x1))) -> b(a(b(a(x1)))) b(x1) -> c(a(c(x1))) Problem 1: SCC Processor: -> Pairs: A(a(x1)) -> A(b(c(a(x1)))) A(a(x1)) -> B(c(a(x1))) A(c(b(x1))) -> A(b(a(x1))) A(c(b(x1))) -> A(x1) A(c(b(x1))) -> B(a(b(a(x1)))) A(c(b(x1))) -> B(a(x1)) B(x1) -> A(c(x1)) -> Rules: a(a(x1)) -> a(b(c(a(x1)))) a(c(b(x1))) -> b(a(b(a(x1)))) b(x1) -> c(a(c(x1))) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: A(a(x1)) -> A(b(c(a(x1)))) A(a(x1)) -> B(c(a(x1))) A(c(b(x1))) -> A(b(a(x1))) A(c(b(x1))) -> A(x1) A(c(b(x1))) -> B(a(b(a(x1)))) A(c(b(x1))) -> B(a(x1)) B(x1) -> A(c(x1)) ->->-> Rules: a(a(x1)) -> a(b(c(a(x1)))) a(c(b(x1))) -> b(a(b(a(x1)))) b(x1) -> c(a(c(x1))) Problem 1: Reduction Pair Processor: -> Pairs: A(a(x1)) -> A(b(c(a(x1)))) A(a(x1)) -> B(c(a(x1))) A(c(b(x1))) -> A(b(a(x1))) A(c(b(x1))) -> A(x1) A(c(b(x1))) -> B(a(b(a(x1)))) A(c(b(x1))) -> B(a(x1)) B(x1) -> A(c(x1)) -> Rules: a(a(x1)) -> a(b(c(a(x1)))) a(c(b(x1))) -> b(a(b(a(x1)))) b(x1) -> c(a(c(x1))) -> Usable rules: a(a(x1)) -> a(b(c(a(x1)))) a(c(b(x1))) -> b(a(b(a(x1)))) b(x1) -> c(a(c(x1))) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 2 ->Bound: 1 ->Interpretation: [a](X) = [1 0;1 0].X [b](X) = [0 1;1 0].X + [0;1] [c](X) = [0 1;0 0].X [A](X) = [1 0;1 0].X + [1;0] [B](X) = [0 1;0 1].X + [1;0] Problem 1:
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