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SRS Stand 10685 pair #381719187
details
property
value
status
complete
benchmark
size-12-alpha-3-num-448.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n107.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
23.0253050327 seconds
cpu usage
90.669549652
max memory
1.36022016E9
stage attributes
key
value
output-size
2303
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 Proof: DP Processor: DPs: a#(x1) -> c#(x1) a#(b(b(x1))) -> a#(x1) a#(b(b(x1))) -> a#(a(x1)) TRS: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 TDG Processor: DPs: a#(x1) -> c#(x1) a#(b(b(x1))) -> a#(x1) a#(b(b(x1))) -> a#(a(x1)) TRS: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 graph: a#(b(b(x1))) -> a#(a(x1)) -> a#(b(b(x1))) -> a#(a(x1)) a#(b(b(x1))) -> a#(a(x1)) -> a#(b(b(x1))) -> a#(x1) a#(b(b(x1))) -> a#(a(x1)) -> a#(x1) -> c#(x1) a#(b(b(x1))) -> a#(x1) -> a#(b(b(x1))) -> a#(a(x1)) a#(b(b(x1))) -> a#(x1) -> a#(b(b(x1))) -> a#(x1) a#(b(b(x1))) -> a#(x1) -> a#(x1) -> c#(x1) SCC Processor: #sccs: 1 #rules: 2 #arcs: 6/9 DPs: a#(b(b(x1))) -> a#(a(x1)) a#(b(b(x1))) -> a#(x1) TRS: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 Arctic Interpretation Processor: dimension: 2 usable rules: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 interpretation: [a#](x0) = [3 1]x0, [0 0] [0] [b](x0) = [1 0]x0 + [2], [0 -&] [-&] [c](x0) = [0 -&]x0 + [0 ], [0 -&] [0] [a](x0) = [1 0 ]x0 + [2] orientation: a#(b(b(x1))) = [4 3]x1 + [5] >= [3 1]x1 + [3] = a#(a(x1)) a#(b(b(x1))) = [4 3]x1 + [5] >= [3 1]x1 = a#(x1) [0 -&] [0] [0 -&] [0] a(x1) = [1 0 ]x1 + [2] >= [1 -&]x1 + [2] = b(c(x1)) [1 0] [2] [1 0] [2] a(b(b(x1))) = [2 1]x1 + [3] >= [2 1]x1 + [3] = b(b(a(a(x1)))) [0 0] [0] c(b(x1)) = [0 0]x1 + [0] >= x1 = x1 problem: DPs: TRS: a(x1) -> b(c(x1)) a(b(b(x1))) -> b(b(a(a(x1)))) c(b(x1)) -> x1 Qed
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