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SRS Stand 10685 pair #381720048
details
property
value
status
complete
benchmark
z074.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n090.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
4.60269212723 seconds
cpu usage
16.933106855
max memory
8.8440832E8
stage attributes
key
value
output-size
8242
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: r(r(x1)) -> s(r(x1)) r(s(x1)) -> s(r(x1)) r(n(x1)) -> s(r(x1)) r(b(x1)) -> u(s(b(x1))) r(u(x1)) -> u(r(x1)) s(u(x1)) -> u(s(x1)) n(u(x1)) -> u(n(x1)) t(r(u(x1))) -> t(c(r(x1))) t(s(u(x1))) -> t(c(r(x1))) t(n(u(x1))) -> t(c(r(x1))) c(u(x1)) -> u(c(x1)) c(s(x1)) -> s(c(x1)) c(r(x1)) -> r(c(x1)) c(n(x1)) -> n(c(x1)) c(n(x1)) -> n(x1) Proof: String Reversal Processor: r(r(x1)) -> r(s(x1)) s(r(x1)) -> r(s(x1)) n(r(x1)) -> r(s(x1)) b(r(x1)) -> b(s(u(x1))) u(r(x1)) -> r(u(x1)) u(s(x1)) -> s(u(x1)) u(n(x1)) -> n(u(x1)) u(r(t(x1))) -> r(c(t(x1))) u(s(t(x1))) -> r(c(t(x1))) u(n(t(x1))) -> r(c(t(x1))) u(c(x1)) -> c(u(x1)) s(c(x1)) -> c(s(x1)) r(c(x1)) -> c(r(x1)) n(c(x1)) -> c(n(x1)) n(c(x1)) -> n(x1) Matrix Interpretation Processor: dim=1 interpretation: [c](x0) = x0, [t](x0) = x0 + 2, [u](x0) = 2x0, [b](x0) = x0, [n](x0) = 2x0, [s](x0) = 2x0, [r](x0) = 4x0 orientation: r(r(x1)) = 16x1 >= 8x1 = r(s(x1)) s(r(x1)) = 8x1 >= 8x1 = r(s(x1)) n(r(x1)) = 8x1 >= 8x1 = r(s(x1)) b(r(x1)) = 4x1 >= 4x1 = b(s(u(x1))) u(r(x1)) = 8x1 >= 8x1 = r(u(x1)) u(s(x1)) = 4x1 >= 4x1 = s(u(x1)) u(n(x1)) = 4x1 >= 4x1 = n(u(x1)) u(r(t(x1))) = 8x1 + 16 >= 4x1 + 8 = r(c(t(x1))) u(s(t(x1))) = 4x1 + 8 >= 4x1 + 8 = r(c(t(x1))) u(n(t(x1))) = 4x1 + 8 >= 4x1 + 8 = r(c(t(x1))) u(c(x1)) = 2x1 >= 2x1 = c(u(x1)) s(c(x1)) = 2x1 >= 2x1 = c(s(x1)) r(c(x1)) = 4x1 >= 4x1 = c(r(x1)) n(c(x1)) = 2x1 >= 2x1 = c(n(x1)) n(c(x1)) = 2x1 >= 2x1 = n(x1) problem: r(r(x1)) -> r(s(x1)) s(r(x1)) -> r(s(x1)) n(r(x1)) -> r(s(x1)) b(r(x1)) -> b(s(u(x1))) u(r(x1)) -> r(u(x1)) u(s(x1)) -> s(u(x1)) u(n(x1)) -> n(u(x1)) u(s(t(x1))) -> r(c(t(x1))) u(n(t(x1))) -> r(c(t(x1))) u(c(x1)) -> c(u(x1)) s(c(x1)) -> c(s(x1))
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