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SRS Stand 10685 pair #381720108
details
property
value
status
complete
benchmark
z093.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n084.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
0.979320049286 seconds
cpu usage
2.663512502
max memory
3.22117632E8
stage attributes
key
value
output-size
918
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: b(c(x1)) -> c(b(x1)) c(b(x1)) -> a(a(a(x1))) a(a(a(a(x1)))) -> b(c(x1)) Proof: Matrix Interpretation Processor: dim=1 interpretation: [a](x0) = x0 + 1, [b](x0) = x0 + 3, [c](x0) = x0 orientation: b(c(x1)) = x1 + 3 >= x1 + 3 = c(b(x1)) c(b(x1)) = x1 + 3 >= x1 + 3 = a(a(a(x1))) a(a(a(a(x1)))) = x1 + 4 >= x1 + 3 = b(c(x1)) problem: b(c(x1)) -> c(b(x1)) c(b(x1)) -> a(a(a(x1))) String Reversal Processor: c(b(x1)) -> b(c(x1)) b(c(x1)) -> a(a(a(x1))) KBO Processor: weight function: w0 = 1 w(b) = w(c) = 1 w(a) = 0 precedence: a > c > b problem: Qed
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