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SRS Stand 10685 pair #381720577
details
property
value
status
complete
benchmark
212263.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n081.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
6.28776597977 seconds
cpu usage
21.729001288
max memory
2.282983424E9
stage attributes
key
value
output-size
13704
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) DependencyPairsProof [EQUIVALENT, 141 ms] (4) QDP (5) DependencyGraphProof [EQUIVALENT, 1 ms] (6) QDP (7) UsableRulesProof [EQUIVALENT, 0 ms] (8) QDP (9) MRRProof [EQUIVALENT, 73 ms] (10) QDP (11) DependencyGraphProof [EQUIVALENT, 0 ms] (12) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 0(1(2(x1))) -> 0(2(1(1(x1)))) 0(1(2(x1))) -> 0(2(1(3(x1)))) 0(1(2(x1))) -> 0(2(1(1(3(x1))))) 0(1(2(x1))) -> 0(2(4(1(1(x1))))) 0(1(2(x1))) -> 0(2(4(1(3(x1))))) 0(3(2(x1))) -> 0(2(1(3(x1)))) 0(3(2(x1))) -> 0(2(1(1(3(x1))))) 0(3(2(x1))) -> 0(0(2(1(1(3(x1)))))) 0(1(1(2(x1)))) -> 0(2(1(1(3(x1))))) 0(1(2(2(x1)))) -> 0(2(2(1(1(x1))))) 0(1(2(2(x1)))) -> 0(2(3(2(1(x1))))) 0(1(3(2(x1)))) -> 0(2(1(4(3(x1))))) 0(1(3(2(x1)))) -> 3(3(0(2(1(x1))))) 0(1(3(2(x1)))) -> 3(0(2(4(1(1(x1)))))) 0(1(5(2(x1)))) -> 5(0(2(1(1(x1))))) 0(3(2(2(x1)))) -> 0(0(2(3(2(x1))))) 0(3(2(2(x1)))) -> 0(0(4(2(3(2(x1)))))) 2(0(3(2(x1)))) -> 1(3(0(2(2(x1))))) 3(0(3(2(x1)))) -> 3(0(0(0(2(3(x1)))))) 3(1(5(2(x1)))) -> 0(2(1(5(3(x1))))) 3(3(5(2(x1)))) -> 3(0(2(1(5(3(x1)))))) 4(5(2(2(x1)))) -> 2(5(0(2(4(1(x1)))))) 5(0(1(2(x1)))) -> 0(2(1(3(4(5(x1)))))) 5(0(2(2(x1)))) -> 2(0(2(4(1(5(x1)))))) 5(0(3(2(x1)))) -> 3(0(2(1(4(5(x1)))))) 5(1(2(2(x1)))) -> 0(2(1(5(2(1(x1)))))) 5(1(2(2(x1)))) -> 2(1(5(2(1(1(x1)))))) 0(1(2(4(2(x1))))) -> 4(2(1(0(2(1(x1)))))) 0(1(2(5(2(x1))))) -> 2(0(2(1(5(4(x1)))))) 0(1(5(1(2(x1))))) -> 1(0(2(1(1(5(x1)))))) 0(1(5(5(2(x1))))) -> 0(2(1(5(5(1(x1)))))) 0(5(0(1(2(x1))))) -> 0(4(5(0(2(1(x1)))))) 0(5(0(3(2(x1))))) -> 0(5(0(0(2(3(x1)))))) 0(5(5(2(2(x1))))) -> 0(2(1(5(5(2(x1)))))) 3(0(3(1(2(x1))))) -> 1(3(3(0(2(3(x1)))))) 3(0(3(4(2(x1))))) -> 1(3(4(0(2(3(x1)))))) 4(5(1(4(2(x1))))) -> 2(4(4(4(1(5(x1)))))) 5(0(1(3(2(x1))))) -> 3(5(0(2(1(3(x1)))))) 5(0(3(1(2(x1))))) -> 0(2(1(4(3(5(x1)))))) 5(0(4(2(2(x1))))) -> 2(0(2(4(1(5(x1)))))) 5(1(0(3(2(x1))))) -> 0(4(3(5(1(2(x1)))))) 5(1(0(3(2(x1))))) -> 5(3(1(1(0(2(x1)))))) 5(1(0(5(2(x1))))) -> 3(5(5(0(2(1(x1)))))) 5(1(0(5(2(x1))))) -> 5(0(2(1(5(5(x1)))))) 5(2(0(3(2(x1))))) -> 0(2(5(2(3(1(x1)))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 2(1(0(x1))) -> 1(1(2(0(x1)))) 2(1(0(x1))) -> 3(1(2(0(x1)))) 2(1(0(x1))) -> 3(1(1(2(0(x1))))) 2(1(0(x1))) -> 1(1(4(2(0(x1))))) 2(1(0(x1))) -> 3(1(4(2(0(x1))))) 2(3(0(x1))) -> 3(1(2(0(x1))))
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