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SRS Stand 10685 pair #381720809
details
property
value
status
complete
benchmark
211857.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n041.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
muterm 5.18
configuration
default
runtime (wallclock)
0.628082990646 seconds
cpu usage
0.636800997
max memory
1.1288576E7
stage attributes
key
value
output-size
62296
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x1) (RULES 0(0(5(1(5(x1))))) -> 1(2(5(5(0(0(x1)))))) 0(0(1(5(x1)))) -> 0(4(1(0(5(x1))))) 0(0(1(x1))) -> 0(0(2(2(1(2(x1)))))) 0(0(1(x1))) -> 0(1(2(0(x1)))) 0(0(1(x1))) -> 0(1(2(4(2(0(x1)))))) 0(0(1(x1))) -> 0(1(3(0(2(x1))))) 0(0(1(x1))) -> 0(1(3(0(4(x1))))) 0(0(1(x1))) -> 0(2(0(1(2(x1))))) 0(0(1(x1))) -> 0(3(0(1(2(x1))))) 0(0(1(x1))) -> 0(3(0(3(1(x1))))) 0(0(1(x1))) -> 0(3(1(0(x1)))) 0(0(1(x1))) -> 0(4(0(4(1(x1))))) 0(0(1(x1))) -> 1(0(4(0(x1)))) 0(0(1(x1))) -> 1(2(0(2(0(x1))))) 0(0(1(x1))) -> 1(2(0(3(0(4(x1)))))) 0(0(1(x1))) -> 1(2(2(0(0(x1))))) 0(0(2(1(x1)))) -> 2(0(3(0(2(1(x1)))))) 0(0(2(1(x1)))) -> 2(3(0(2(0(1(x1)))))) 0(5(1(x1))) -> 0(2(3(1(5(x1))))) 0(5(1(x1))) -> 0(3(1(5(2(x1))))) 0(5(1(x1))) -> 0(3(1(5(x1)))) 0(5(1(x1))) -> 0(3(1(2(5(2(x1)))))) 0(5(1(x1))) -> 0(4(5(1(x1)))) 0(5(3(0(1(x1))))) -> 1(0(5(3(0(4(x1)))))) 0(5(3(4(1(x1))))) -> 1(0(3(5(4(5(x1)))))) 0(5(4(0(1(x1))))) -> 0(1(3(0(4(5(x1)))))) 0(1(0(1(x1)))) -> 1(0(2(0(1(x1))))) 0(1(1(1(x1)))) -> 1(1(3(1(0(x1))))) 0(1(1(x1))) -> 0(2(1(1(x1)))) 0(1(1(x1))) -> 0(3(1(1(x1)))) 0(1(1(x1))) -> 1(0(3(1(2(4(x1)))))) 0(1(1(x1))) -> 1(0(4(2(1(2(x1)))))) 0(1(1(x1))) -> 1(1(2(4(3(0(x1)))))) 0(1(1(x1))) -> 1(1(3(0(4(x1))))) 0(1(1(x1))) -> 1(2(0(2(1(x1))))) 0(1(1(x1))) -> 1(2(1(0(4(4(x1)))))) 0(1(1(x1))) -> 1(2(2(1(3(0(x1)))))) 5(0(1(1(x1)))) -> 1(5(1(2(0(x1))))) 5(0(1(x1))) -> 5(0(2(1(2(4(x1)))))) 5(0(1(x1))) -> 5(1(2(3(0(4(x1)))))) 5(0(1(x1))) -> 5(1(2(4(0(x1))))) 5(3(0(1(x1)))) -> 5(1(2(3(0(x1))))) 5(3(1(5(x1)))) -> 5(3(1(2(5(x1))))) 5(3(2(1(x1)))) -> 1(2(3(5(2(x1))))) 5(4(0(1(x1)))) -> 1(2(5(0(4(x1))))) 5(4(2(1(1(x1))))) -> 5(4(1(2(1(2(x1)))))) ) Problem 1: Dependency Pairs Processor: -> Pairs: 0#(0(5(1(5(x1))))) -> 0#(0(x1)) 0#(0(5(1(5(x1))))) -> 0#(x1) 0#(0(5(1(5(x1))))) -> 5#(0(0(x1))) 0#(0(5(1(5(x1))))) -> 5#(5(0(0(x1)))) 0#(0(1(5(x1)))) -> 0#(5(x1)) 0#(0(1(5(x1)))) -> 0#(4(1(0(5(x1))))) 0#(0(1(x1))) -> 0#(0(x1)) 0#(0(1(x1))) -> 0#(1(2(0(x1)))) 0#(0(1(x1))) -> 0#(1(2(4(2(0(x1)))))) 0#(0(1(x1))) -> 0#(2(0(x1))) 0#(0(1(x1))) -> 0#(3(1(0(x1)))) 0#(0(1(x1))) -> 0#(4(0(x1))) 0#(0(1(x1))) -> 0#(x1) 0#(0(2(1(x1)))) -> 0#(1(x1)) 0#(0(2(1(x1)))) -> 0#(2(0(1(x1)))) 0#(5(1(x1))) -> 0#(2(3(1(5(x1))))) 0#(5(1(x1))) -> 0#(3(1(5(x1)))) 0#(5(1(x1))) -> 5#(x1) 0#(5(3(4(1(x1))))) -> 0#(3(5(4(5(x1))))) 0#(5(3(4(1(x1))))) -> 5#(4(5(x1))) 0#(5(3(4(1(x1))))) -> 5#(x1) 0#(5(4(0(1(x1))))) -> 0#(1(3(0(4(5(x1)))))) 0#(5(4(0(1(x1))))) -> 0#(4(5(x1))) 0#(5(4(0(1(x1))))) -> 5#(x1) 0#(1(0(1(x1)))) -> 0#(2(0(1(x1)))) 0#(1(1(1(x1)))) -> 0#(x1) 0#(1(1(x1))) -> 0#(x1) 5#(0(1(1(x1)))) -> 0#(x1) 5#(0(1(1(x1)))) -> 5#(1(2(0(x1)))) 5#(0(1(x1))) -> 0#(x1) 5#(0(1(x1))) -> 5#(1(2(4(0(x1))))) 5#(3(0(1(x1)))) -> 0#(x1) 5#(3(0(1(x1)))) -> 5#(1(2(3(0(x1))))) 5#(3(1(5(x1)))) -> 5#(3(1(2(5(x1))))) -> Rules: 0(0(5(1(5(x1))))) -> 1(2(5(5(0(0(x1))))))
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