details

property	value
status	complete
benchmark	abaaaa-aaaaabaaabaab.srs.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n048.star.cs.uiowa.edu
space	Wenzel_16

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.69027590752 seconds
cpu usage	4.042377707
max memory	3.16588032E8

stage attributes

key	value
output-size	3344
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 5 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(a(a(x1)))))) -> a(a(a(a(a(b(a(a(a(b(a(a(b(x1))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(a(x1)))))) -> b(a(a(b(a(a(a(b(a(a(a(a(a(x1))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(b(a(x1)))))) -> b(a(a(b(a(a(a(b(a(a(a(a(a(x1))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(b(x))))) -> b(a(a(b(a(a(a(b(a(a(a(a(x)))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(x))))) -> b(a(a(b(a(a(a(b(a(a(a(a(x)))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(b(x))))) -> b(a(a(b(a(a(a(b(a(a(a(a(x)))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 520, 521, 522, 523, 524, 525, 526, 527, 528, 529, 530, 531, 532, 533, 534, 535, 536, 537, 538, 539, 540, 541, 542, 543 Node 520 is start node and node 521 is final node. Those nodes are connected through the following edges: * 520 to 522 labelled b_1(0)* 521 to 521 labelled #_1(0)* 522 to 523 labelled a_1(0)* 523 to 524 labelled a_1(0)* 524 to 525 labelled b_1(0)* 525 to 526 labelled a_1(0)* 526 to 527 labelled a_1(0)* 527 to 528 labelled a_1(0)* 528 to 529 labelled b_1(0)* 529 to 530 labelled a_1(0)* 529 to 533 labelled b_1(1)* 530 to 531 labelled a_1(0)* 530 to 533 labelled b_1(1)* 531 to 532 labelled a_1(0)* 531 to 533 labelled b_1(1)* 532 to 521 labelled a_1(0)* 532 to 533 labelled b_1(1)* 533 to 534 labelled a_1(1)* 534 to 535 labelled a_1(1)* 535 to 536 labelled b_1(1)* 536 to 537 labelled a_1(1)* 537 to 538 labelled a_1(1)* 538 to 539 labelled a_1(1)* 539 to 540 labelled b_1(1)* 540 to 541 labelled a_1(1)* 540 to 533 labelled b_1(1)* 541 to 542 labelled a_1(1)* 541 to 533 labelled b_1(1)* 542 to 543 labelled a_1(1)* 542 to 533 labelled b_1(1)* 543 to 521 labelled a_1(1)* 543 to 533 labelled b_1(1) ---------------------------------------- (6) YES popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to SRS Stand 10685