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SRS Stand 10685 pair #381723262
details
property
value
status
complete
benchmark
230948.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n191.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
4.57529997826 seconds
cpu usage
14.546791811
max memory
1.359552512E9
stage attributes
key
value
output-size
6668
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 284 ms] (2) QTRS (3) Overlay + Local Confluence [EQUIVALENT, 0 ms] (4) QTRS (5) DependencyPairsProof [EQUIVALENT, 27 ms] (6) QDP (7) DependencyGraphProof [EQUIVALENT, 0 ms] (8) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 0(x1) -> 1(x1) 0(0(x1)) -> 0(x1) 3(4(5(x1))) -> 4(3(5(x1))) 2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(x1))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) -> 1(0(1(1(1(0(1(0(1(1(1(0(1(1(0(0(0(1(0(1(1(1(1(1(0(1(1(0(0(1(0(1(1(1(1(1(1(1(1(0(0(0(1(1(0(1(1(1(0(0(0(0(0(0(0(0(1(0(1(1(1(0(0(0(1(1(1(1(0(0(1(0(0(1(0(1(0(0(1(0(1(0(1(1(0(1(0(1(0(1(1(0(0(0(0(1(1(0(1(1(0(0(1(0(0(0(0(1(0(1(0(0(1(0(0(0(1(0(1(1(0(0(1(0(0(0(0(0(1(1(0(1(0(0(1(0(1(1(1(0(0(0(1(1(1(0(0(1(0(1(0(0(1(0(1(0(1(0(0(1(1(0(0(0(1(1(1(0(0(1(1(0(0(0(1(0(1(0(0(0(1(1(1(0(0(0(1(1(1(0(1(0(1(0(1(0(1(1(1(1(1(0(1(0(x1)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) 0(0(0(0(0(0(0(0(0(1(1(0(1(1(1(1(0(0(1(0(0(1(1(1(1(1(0(1(1(0(0(0(1(0(0(1(1(1(0(1(0(1(0(0(1(0(1(0(1(1(0(0(1(0(0(0(0(1(0(0(0(0(1(0(1(1(1(0(0(0(1(1(1(1(1(1(1(1(1(0(1(0(0(0(1(0(1(1(1(1(0(0(0(1(0(1(1(0(0(1(1(1(0(0(0(1(0(1(0(0(0(1(1(0(0(0(0(1(0(1(1(1(0(1(0(0(1(0(0(0(1(1(1(0(0(0(0(1(1(1(1(0(1(1(0(0(1(0(0(1(0(1(1(0(1(0(0(0(0(0(0(1(1(0(1(1(0(0(1(1(0(0(1(0(1(1(1(0(1(0(0(0(1(1(0(1(0(1(1(1(1(0(1(1(0(0(1(1(1(0(0(1(0(1(1(1(1(1(x1)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) -> 2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(x1))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(0(x_1)) = 6 + x_1 POL(1(x_1)) = 5 + x_1 POL(2(x_1)) = 9 + x_1 POL(3(x_1)) = x_1 POL(4(x_1)) = x_1 POL(5(x_1)) = x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: 0(x1) -> 1(x1) 0(0(x1)) -> 0(x1) 2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(x1))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) -> 1(0(1(1(1(0(1(0(1(1(1(0(1(1(0(0(0(1(0(1(1(1(1(1(0(1(1(0(0(1(0(1(1(1(1(1(1(1(1(0(0(0(1(1(0(1(1(1(0(0(0(0(0(0(0(0(1(0(1(1(1(0(0(0(1(1(1(1(0(0(1(0(0(1(0(1(0(0(1(0(1(0(1(1(0(1(0(1(0(1(1(0(0(0(0(1(1(0(1(1(0(0(1(0(0(0(0(1(0(1(0(0(1(0(0(0(1(0(1(1(0(0(1(0(0(0(0(0(1(1(0(1(0(0(1(0(1(1(1(0(0(0(1(1(1(0(0(1(0(1(0(0(1(0(1(0(1(0(0(1(1(0(0(0(1(1(1(0(0(1(1(0(0(0(1(0(1(0(0(0(1(1(1(0(0(0(1(1(1(0(1(0(1(0(1(0(1(1(1(1(1(0(1(0(x1)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) 0(0(0(0(0(0(0(0(0(1(1(0(1(1(1(1(0(0(1(0(0(1(1(1(1(1(0(1(1(0(0(0(1(0(0(1(1(1(0(1(0(1(0(0(1(0(1(0(1(1(0(0(1(0(0(0(0(1(0(0(0(0(1(0(1(1(1(0(0(0(1(1(1(1(1(1(1(1(1(0(1(0(0(0(1(0(1(1(1(1(0(0(0(1(0(1(1(0(0(1(1(1(0(0(0(1(0(1(0(0(0(1(1(0(0(0(0(1(0(1(1(1(0(1(0(0(1(0(0(0(1(1(1(0(0(0(0(1(1(1(1(0(1(1(0(0(1(0(0(1(0(1(1(0(1(0(0(0(0(0(0(1(1(0(1(1(0(0(1(1(0(0(1(0(1(1(1(0(1(0(0(0(1(1(0(1(0(1(1(1(1(0(1(1(0(0(1(1(1(0(0(1(0(1(1(1(1(1(x1)))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) -> 2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(2(x1))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 3(4(5(x1))) -> 4(3(5(x1))) Q is empty. ---------------------------------------- (3) Overlay + Local Confluence (EQUIVALENT) The TRS is overlay and locally confluent. By [NOC] we can switch to innermost. ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 3(4(5(x1))) -> 4(3(5(x1))) The set Q consists of the following terms: 3(4(5(x0))) ---------------------------------------- (5) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (6) Obligation: Q DP problem: The TRS P consists of the following rules:
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