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SRS Stand 10685 pair #381723263
details
property
value
status
complete
benchmark
size-12-alpha-3-num-135.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n073.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
14.2025780678 seconds
cpu usage
51.681417197
max memory
3.920166912E9
stage attributes
key
value
output-size
2202
starexec-result
NO
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 1083 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(x1) -> x1 a(b(x1)) -> x1 b(b(x1)) -> c(x1) c(a(x1)) -> a(a(b(c(x1)))) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "c a a a a a -> a c a a a a a b c b c" c a a a a a -> a c a a a a a b c b c by OverlapClosure OC 2"c a a -> a c c by OverlapClosure OC 3"c a a -> a b b c by OverlapClosure OC 3"c a a -> a b a b c by OverlapClosure OC 2"c a -> a b c by OverlapClosure OC 3"c a -> a a b c by original rule (OC 1)""a -> by original rule (OC 1)"""c a -> a b c by OverlapClosure OC 3"c a -> a a b c by original rule (OC 1)""a -> by original rule (OC 1)""""a -> by original rule (OC 1)"""b b -> c by original rule (OC 1)"""c a a a -> a a a a a b c b c by OverlapClosure OC 3"c a a a -> a a a c a b c by OverlapClosure OC 3"c a a a -> a a c a a b c by OverlapClosure OC 2"c a a -> a a c c by OverlapClosure OC 3"c a a -> a a b b c by OverlapClosure OC 3"c a a -> a a b a b c by OverlapClosure OC 2"c a -> a a b c by original rule (OC 1)""c a -> a b c by OverlapClosure OC 3"c a -> a a b c by original rule (OC 1)""a -> by original rule (OC 1)""""a -> by original rule (OC 1)"""b b -> c by original rule (OC 1)"""c a -> a a b c by original rule (OC 1)"""c a -> a c by OverlapClosure OC 3"c a -> a a b c by original rule (OC 1)""a b -> by original rule (OC 1)""""c a -> a a b c by original rule (OC 1)"" ---------------------------------------- (2) NO
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