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SRS Stand 10685 pair #381723413
details
property
value
status
complete
benchmark
size-12-alpha-3-num-328.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n112.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
6.18963217735 seconds
cpu usage
21.397325913
max memory
2.81819136E9
stage attributes
key
value
output-size
2139
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 1183 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(x1) -> b(x1) a(x1) -> b(b(c(x1))) c(a(b(x1))) -> a(c(a(x1))) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "c a b b b b b -> b b c a b b b b b c c a c c a" c a b b b b b -> b b c a b b b b b c c a c c a by OverlapClosure OC 3"c a b b b b b -> b b c a b b a b b c c a c c a by OverlapClosure OC 3"c a b b b b b -> b b c a b b a a c a c c a by OverlapClosure OC 3"c a b b b b b -> a a b b a a c a c c a by OverlapClosure OC 2"c a b -> a c a by original rule (OC 1)""c a b b b b -> a b b a a c a c c a by OverlapClosure OC 2"c a b -> a c a by original rule (OC 1)""c a b b b -> b b a a c a c c a by OverlapClosure OC 3"c a b b b -> b b a c a b c c a by OverlapClosure OC 3"c a b b b -> a a b b c c a by OverlapClosure OC 3"c a b b b -> a a a c a by OverlapClosure OC 2"c a b -> a c a by original rule (OC 1)""c a b b -> a a c a by OverlapClosure OC 2"c a b -> a c a by original rule (OC 1)""c a b -> a c a by original rule (OC 1)""""a -> b b c by original rule (OC 1)"""a a b -> b b a c a by OverlapClosure OC 2"a -> b b c by original rule (OC 1)""c a b -> a c a by original rule (OC 1)""""c a b -> a c a by original rule (OC 1)"""""a -> b b c by original rule (OC 1)"""a -> b b c by original rule (OC 1)"""a -> b by original rule (OC 1)" ---------------------------------------- (2) NO
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