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SRS Stand 10685 pair #381724012
details
property
value
status
complete
benchmark
96274.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n096.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
3.35364294052 seconds
cpu usage
10.618222143
max memory
1.027846144E9
stage attributes
key
value
output-size
6919
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 242 ms] (2) QTRS (3) AAECC Innermost [EQUIVALENT, 9 ms] (4) QTRS (5) DependencyPairsProof [EQUIVALENT, 1 ms] (6) QDP (7) DependencyGraphProof [EQUIVALENT, 4 ms] (8) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: 0(1(2(3(x1)))) -> 4(4(2(3(x1)))) 5(3(3(5(4(x1))))) -> 5(1(0(2(x1)))) 2(3(1(5(0(5(x1)))))) -> 2(1(3(5(0(5(x1)))))) 5(3(3(5(5(4(x1)))))) -> 4(2(4(3(2(x1))))) 5(1(4(5(1(1(5(x1))))))) -> 1(4(0(2(3(2(5(x1))))))) 3(3(4(3(1(3(0(5(x1)))))))) -> 3(5(2(4(5(0(5(2(x1)))))))) 3(1(2(2(2(1(3(1(3(x1))))))))) -> 1(4(3(1(5(0(2(2(x1)))))))) 3(4(2(0(5(2(3(5(3(x1))))))))) -> 3(5(4(4(2(2(0(5(1(x1))))))))) 5(5(1(3(3(5(4(0(0(x1))))))))) -> 3(1(0(1(4(2(4(3(x1)))))))) 3(0(2(5(1(5(0(1(5(0(x1)))))))))) -> 1(2(2(0(0(4(3(4(4(x1))))))))) 3(5(5(4(4(4(2(0(0(3(x1)))))))))) -> 1(1(2(3(2(3(4(1(x1)))))))) 3(0(4(3(3(5(0(4(4(0(4(2(x1)))))))))))) -> 3(4(5(5(3(2(0(5(1(4(2(x1))))))))))) 5(2(0(4(5(0(2(1(1(1(2(0(x1)))))))))))) -> 3(0(0(2(2(4(5(1(3(1(0(x1))))))))))) 5(5(4(3(3(4(5(4(5(0(0(4(5(x1))))))))))))) -> 5(0(1(0(3(1(4(1(2(3(1(x1))))))))))) 5(2(1(3(0(2(2(4(5(2(2(0(0(1(x1)))))))))))))) -> 3(4(5(1(4(3(3(5(0(3(0(1(x1)))))))))))) 3(1(5(2(5(5(3(3(4(4(5(2(3(2(4(x1))))))))))))))) -> 3(0(5(4(4(4(2(0(0(1(4(3(2(4(x1)))))))))))))) 4(5(5(4(3(4(4(2(4(2(4(3(3(3(3(x1))))))))))))))) -> 4(5(0(0(4(4(5(4(4(3(4(0(0(0(x1)))))))))))))) 0(1(2(4(3(1(1(4(1(5(0(2(5(3(2(4(3(x1))))))))))))))))) -> 4(2(2(1(3(1(3(0(4(5(1(2(2(5(5(4(1(x1))))))))))))))))) 2(4(3(0(4(2(0(0(2(5(1(0(2(0(0(4(4(x1))))))))))))))))) -> 5(4(1(2(1(2(1(0(2(0(4(3(1(0(0(2(x1)))))))))))))))) 3(3(3(1(0(2(1(1(5(2(4(0(0(4(5(2(2(0(2(x1))))))))))))))))))) -> 3(2(2(3(1(5(5(5(3(0(3(1(4(3(2(3(1(x1))))))))))))))))) 5(3(2(2(5(2(1(3(0(2(4(3(2(5(3(3(0(5(4(x1))))))))))))))))))) -> 1(3(0(3(3(4(5(5(0(5(5(4(0(2(1(1(0(0(2(x1))))))))))))))))))) 5(4(5(5(5(2(0(1(2(1(0(1(2(1(5(3(1(3(1(x1))))))))))))))))))) -> 0(0(3(5(3(0(2(0(1(4(0(5(4(3(0(2(4(1(x1)))))))))))))))))) 4(0(4(0(5(1(0(3(2(5(3(1(3(0(2(5(3(5(0(0(x1)))))))))))))))))))) -> 1(5(3(5(2(0(5(4(4(5(0(1(4(4(3(1(3(2(5(1(x1)))))))))))))))))))) 5(4(2(1(3(2(5(4(2(2(0(0(5(5(1(0(5(1(3(0(x1)))))))))))))))))))) -> 4(4(2(4(0(1(3(2(5(1(3(4(4(0(0(1(1(1(2(0(x1)))))))))))))))))))) 3(0(4(5(4(1(4(3(5(5(3(5(4(0(1(4(3(5(0(3(2(x1))))))))))))))))))))) -> 1(2(4(1(1(2(5(4(2(4(0(4(2(5(1(4(2(1(3(1(2(x1))))))))))))))))))))) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(0(x_1)) = 6 + x_1 POL(1(x_1)) = 7 + x_1 POL(2(x_1)) = 6 + x_1 POL(3(x_1)) = 9 + x_1 POL(4(x_1)) = 5 + x_1 POL(5(x_1)) = 7 + x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: 0(1(2(3(x1)))) -> 4(4(2(3(x1)))) 5(3(3(5(4(x1))))) -> 5(1(0(2(x1)))) 5(3(3(5(5(4(x1)))))) -> 4(2(4(3(2(x1))))) 5(1(4(5(1(1(5(x1))))))) -> 1(4(0(2(3(2(5(x1))))))) 3(3(4(3(1(3(0(5(x1)))))))) -> 3(5(2(4(5(0(5(2(x1)))))))) 3(1(2(2(2(1(3(1(3(x1))))))))) -> 1(4(3(1(5(0(2(2(x1)))))))) 3(4(2(0(5(2(3(5(3(x1))))))))) -> 3(5(4(4(2(2(0(5(1(x1))))))))) 5(5(1(3(3(5(4(0(0(x1))))))))) -> 3(1(0(1(4(2(4(3(x1)))))))) 3(0(2(5(1(5(0(1(5(0(x1)))))))))) -> 1(2(2(0(0(4(3(4(4(x1))))))))) 3(5(5(4(4(4(2(0(0(3(x1)))))))))) -> 1(1(2(3(2(3(4(1(x1)))))))) 3(0(4(3(3(5(0(4(4(0(4(2(x1)))))))))))) -> 3(4(5(5(3(2(0(5(1(4(2(x1))))))))))) 5(2(0(4(5(0(2(1(1(1(2(0(x1)))))))))))) -> 3(0(0(2(2(4(5(1(3(1(0(x1))))))))))) 5(5(4(3(3(4(5(4(5(0(0(4(5(x1))))))))))))) -> 5(0(1(0(3(1(4(1(2(3(1(x1))))))))))) 5(2(1(3(0(2(2(4(5(2(2(0(0(1(x1)))))))))))))) -> 3(4(5(1(4(3(3(5(0(3(0(1(x1)))))))))))) 3(1(5(2(5(5(3(3(4(4(5(2(3(2(4(x1))))))))))))))) -> 3(0(5(4(4(4(2(0(0(1(4(3(2(4(x1)))))))))))))) 4(5(5(4(3(4(4(2(4(2(4(3(3(3(3(x1))))))))))))))) -> 4(5(0(0(4(4(5(4(4(3(4(0(0(0(x1)))))))))))))) 0(1(2(4(3(1(1(4(1(5(0(2(5(3(2(4(3(x1))))))))))))))))) -> 4(2(2(1(3(1(3(0(4(5(1(2(2(5(5(4(1(x1))))))))))))))))) 2(4(3(0(4(2(0(0(2(5(1(0(2(0(0(4(4(x1))))))))))))))))) -> 5(4(1(2(1(2(1(0(2(0(4(3(1(0(0(2(x1)))))))))))))))) 3(3(3(1(0(2(1(1(5(2(4(0(0(4(5(2(2(0(2(x1))))))))))))))))))) -> 3(2(2(3(1(5(5(5(3(0(3(1(4(3(2(3(1(x1))))))))))))))))) 5(3(2(2(5(2(1(3(0(2(4(3(2(5(3(3(0(5(4(x1))))))))))))))))))) -> 1(3(0(3(3(4(5(5(0(5(5(4(0(2(1(1(0(0(2(x1))))))))))))))))))) 5(4(5(5(5(2(0(1(2(1(0(1(2(1(5(3(1(3(1(x1))))))))))))))))))) -> 0(0(3(5(3(0(2(0(1(4(0(5(4(3(0(2(4(1(x1)))))))))))))))))) 4(0(4(0(5(1(0(3(2(5(3(1(3(0(2(5(3(5(0(0(x1)))))))))))))))))))) -> 1(5(3(5(2(0(5(4(4(5(0(1(4(4(3(1(3(2(5(1(x1)))))))))))))))))))) 5(4(2(1(3(2(5(4(2(2(0(0(5(5(1(0(5(1(3(0(x1)))))))))))))))))))) -> 4(4(2(4(0(1(3(2(5(1(3(4(4(0(0(1(1(1(2(0(x1)))))))))))))))))))) 3(0(4(5(4(1(4(3(5(5(3(5(4(0(1(4(3(5(0(3(2(x1))))))))))))))))))))) -> 1(2(4(1(1(2(5(4(2(4(0(4(2(5(1(4(2(1(3(1(2(x1)))))))))))))))))))))
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