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SRS Stand 10685 pair #381724013
details
property
value
status
complete
benchmark
96274.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n003.star.cs.uiowa.edu
space
ICFP_2010
run statistics
property
value
solver
NaTT
configuration
Default
runtime (wallclock)
19.4300129414 seconds
cpu usage
19.428258479
max memory
7.8036992E7
stage attributes
key
value
output-size
2948
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_Default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Input TRS: 1: 0(1(2(3(x1)))) -> 4(4(2(3(x1)))) 2: 5(3(3(5(4(x1))))) -> 5(1(0(2(x1)))) 3: 2(3(1(5(0(5(x1)))))) -> 2(1(3(5(0(5(x1)))))) 4: 5(3(3(5(5(4(x1)))))) -> 4(2(4(3(2(x1))))) 5: 5(1(4(5(1(1(5(x1))))))) -> 1(4(0(2(3(2(5(x1))))))) 6: 3(3(4(3(1(3(0(5(x1)))))))) -> 3(5(2(4(5(0(5(2(x1)))))))) 7: 3(1(2(2(2(1(3(1(3(x1))))))))) -> 1(4(3(1(5(0(2(2(x1)))))))) 8: 3(4(2(0(5(2(3(5(3(x1))))))))) -> 3(5(4(4(2(2(0(5(1(x1))))))))) 9: 5(5(1(3(3(5(4(0(0(x1))))))))) -> 3(1(0(1(4(2(4(3(x1)))))))) 10: 3(0(2(5(1(5(0(1(5(0(x1)))))))))) -> 1(2(2(0(0(4(3(4(4(x1))))))))) 11: 3(5(5(4(4(4(2(0(0(3(x1)))))))))) -> 1(1(2(3(2(3(4(1(x1)))))))) 12: 3(0(4(3(3(5(0(4(4(0(4(2(x1)))))))))))) -> 3(4(5(5(3(2(0(5(1(4(2(x1))))))))))) 13: 5(2(0(4(5(0(2(1(1(1(2(0(x1)))))))))))) -> 3(0(0(2(2(4(5(1(3(1(0(x1))))))))))) 14: 5(5(4(3(3(4(5(4(5(0(0(4(5(x1))))))))))))) -> 5(0(1(0(3(1(4(1(2(3(1(x1))))))))))) 15: 5(2(1(3(0(2(2(4(5(2(2(0(0(1(x1)))))))))))))) -> 3(4(5(1(4(3(3(5(0(3(0(1(x1)))))))))))) 16: 3(1(5(2(5(5(3(3(4(4(5(2(3(2(4(x1))))))))))))))) -> 3(0(5(4(4(4(2(0(0(1(4(3(2(4(x1)))))))))))))) 17: 4(5(5(4(3(4(4(2(4(2(4(3(3(3(3(x1))))))))))))))) -> 4(5(0(0(4(4(5(4(4(3(4(0(0(0(x1)))))))))))))) 18: 0(1(2(4(3(1(1(4(1(5(0(2(5(3(2(4(3(x1))))))))))))))))) -> 4(2(2(1(3(1(3(0(4(5(1(2(2(5(5(4(1(x1))))))))))))))))) 19: 2(4(3(0(4(2(0(0(2(5(1(0(2(0(0(4(4(x1))))))))))))))))) -> 5(4(1(2(1(2(1(0(2(0(4(3(1(0(0(2(x1)))))))))))))))) 20: 3(3(3(1(0(2(1(1(5(2(4(0(0(4(5(2(2(0(2(x1))))))))))))))))))) -> 3(2(2(3(1(5(5(5(3(0(3(1(4(3(2(3(1(x1))))))))))))))))) 21: 5(3(2(2(5(2(1(3(0(2(4(3(2(5(3(3(0(5(4(x1))))))))))))))))))) -> 1(3(0(3(3(4(5(5(0(5(5(4(0(2(1(1(0(0(2(x1))))))))))))))))))) 22: 5(4(5(5(5(2(0(1(2(1(0(1(2(1(5(3(1(3(1(x1))))))))))))))))))) -> 0(0(3(5(3(0(2(0(1(4(0(5(4(3(0(2(4(1(x1)))))))))))))))))) 23: 4(0(4(0(5(1(0(3(2(5(3(1(3(0(2(5(3(5(0(0(x1)))))))))))))))))))) -> 1(5(3(5(2(0(5(4(4(5(0(1(4(4(3(1(3(2(5(1(x1)))))))))))))))))))) 24: 5(4(2(1(3(2(5(4(2(2(0(0(5(5(1(0(5(1(3(0(x1)))))))))))))))))))) -> 4(4(2(4(0(1(3(2(5(1(3(4(4(0(0(1(1(1(2(0(x1)))))))))))))))))))) 25: 3(0(4(5(4(1(4(3(5(5(3(5(4(0(1(4(3(5(0(3(2(x1))))))))))))))))))))) -> 1(2(4(1(1(2(5(4(2(4(0(4(2(5(1(4(2(1(3(1(2(x1))))))))))))))))))))) Number of strict rules: 25 Direct POLO(bPol) ... removes: 18 4 15 8 1 16 21 19 17 22 5 10 7 20 25 14 12 23 24 11 9 13 6 2 1 w: x1 + 3 4 w: x1 + 3 5 w: x1 + 5 3 w: x1 + 5 0 w: x1 + 4 2 w: x1 + 3 Number of strict rules: 1 Direct POLO(bPol) ... removes: 3 1 w: x1 + 1 4 w: x1 + 1 5 w: x1 + 3 3 w: 2 * x1 + 9 0 w: x1 + 1 2 w: x1 + 1 Number of strict rules: 0
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