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TRS Relat 75837 pair #381724835
details
property
value
status
complete
benchmark
assoc.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n090.star.cs.uiowa.edu
space
Mixed_relative_TRS
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.76255679131 seconds
cpu usage
4.067042378
max memory
2.79085056E8
stage attributes
key
value
output-size
1711
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given RelTRS could be disproven: (0) RelTRS (1) RelTRSLoopFinderProof [COMPLETE, 66 ms] (2) NO ---------------------------------------- (0) Obligation: Relative term rewrite system: The relative TRS consists of the following R rules: f(a, x) -> f(x, f(b, x)) The relative TRS consists of the following S rules: f(f(x, y), z) -> f(x, f(y, z)) f(x, f(y, z)) -> f(f(x, y), z) ---------------------------------------- (1) RelTRSLoopFinderProof (COMPLETE) The following loop was found: ---------- Loop: ---------- f(a, f(x', f(y', a))) -> f(a, f(f(x', y'), a)) with rule f(x'', f(y'', z)) -> f(f(x'', y''), z) at position [1] and matcher [x'' / x', y'' / y', z / a] f(a, f(f(x', y'), a)) -> f(f(f(x', y'), a), f(b, f(f(x', y'), a))) with rule f(a, x) -> f(x, f(b, x)) at position [] and matcher [x / f(f(x', y'), a)] f(f(f(x', y'), a), f(b, f(f(x', y'), a))) -> f(f(x', y'), f(a, f(b, f(f(x', y'), a)))) with rule f(f(x, y), z) -> f(x, f(y, z)) at position [] and matcher [x / f(x', y'), y / a, z / f(b, f(f(x', y'), a))] Now an instance of the first term with Matcher [x' / b, y' / f(x', y')] occurs in the last term at position [1]. Context: f(f(x', y'), []) Therefore, the relative TRS problem does not terminate. ---------------------------------------- (2) NO
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