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TRS Relat 75837 pair #381724911
details
property
value
status
complete
benchmark
invNSS03.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n113.star.cs.uiowa.edu
space
INVY_15
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
1.04772496223 seconds
cpu usage
2.760571691
max memory
2.29380096E8
stage attributes
key
value
output-size
5838
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: strict: f(x,0()) -> s(x) g(x) -> h(x,gen()) h(0(),x) -> f(x,x) a() -> b() weak: gen() -> s(gen()) Proof: Matrix Interpretation Processor: dim=4 interpretation: [0] [0] [b] = [0] [0], [1] [0] [a] = [0] [0], [2 0 0 0] [3 1 2 1] [0] [0 0 0 0] [1 1 0 3] [0] [h](x0, x1) = [0 0 0 0]x0 + [1 2 2 1]x1 + [1] [0 0 0 0] [3 0 1 3] [0], [0] [0] [gen] = [0] [1], [3 1 2 0] [1] [0 0 0 0] [3] [g](x0) = [0 0 0 0]x0 + [2] [0 0 0 0] [3], [1 0 0 0] [0] [1 0 0 0] [0] [s](x0) = [0 0 0 0]x0 + [0] [0 0 0 0] [1], [1 1 0 0] [2 0 0 1] [0] [1 0 0 1] [0 0 0 2] [0] [f](x0, x1) = [0 1 1 1]x0 + [1 1 1 0]x1 + [1] [1 0 0 1] [2 0 1 0] [0], [0] [1] [0] = [1] [1] orientation: [1 1 0 0] [1] [1 0 0 0] [0] [1 0 0 1] [2] [1 0 0 0] [0] f(x,0()) = [0 1 1 1]x + [3] >= [0 0 0 0]x + [0] = s(x) [1 0 0 1] [1] [0 0 0 0] [1] [3 1 2 0] [1] [2 0 0 0] [1] [0 0 0 0] [3] [0 0 0 0] [3] g(x) = [0 0 0 0]x + [2] >= [0 0 0 0]x + [2] = h(x,gen()) [0 0 0 0] [3] [0 0 0 0] [3] [3 1 2 1] [0] [3 1 0 1] [0] [1 1 0 3] [0] [1 0 0 3] [0] h(0(),x) = [1 2 2 1]x + [1] >= [1 2 2 1]x + [1] = f(x,x) [3 0 1 3] [0] [3 0 1 1] [0] [1] [0] [0] [0] a() = [0] >= [0] = b() [0] [0] [0] [0] [0] [0] gen() = [0] >= [0] = s(gen()) [1] [1] problem: strict: g(x) -> h(x,gen()) h(0(),x) -> f(x,x) weak: gen() -> s(gen()) Matrix Interpretation Processor: dim=5 interpretation: [1 0 0 1 0] [2 3 2 1 1] [0] [0 0 0 0 0] [1 1 0 0 1] [0] [h](x0, x1) = [0 0 0 0 2]x0 + [0 2 1 3 0]x1 + [0] [0 0 1 0 0] [0 2 1 0 0] [1] [0 0 0 0 0] [1 0 0 0 0] [2],
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