details

property	value
status	complete
benchmark	rt3-6.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n090.star.cs.uiowa.edu
space	Relative_05

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	2.13167619705 seconds
cpu usage	50.534876407
max memory	3.221868544E9

stage attributes

key	value
output-size	2014
starexec-result	NO

output

/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given RelTRS could be disproven: (0) RelTRS (1) RelTRS Reverse [EQUIVALENT, 0 ms] (2) RelTRS (3) RelTRSLoopFinderProof [COMPLETE, 0 ms] (4) NO ---------------------------------------- (0) Obligation: Relative term rewrite system: The relative TRS consists of the following R rules: b(a(x)) -> a(b(x)) The relative TRS consists of the following S rules: a(x) -> a(a(x)) b(x) -> b(b(x)) ---------------------------------------- (1) RelTRS Reverse (EQUIVALENT) We have reversed the following relative TRS [REVERSE]: The set of rules R is b(a(x)) -> a(b(x)) The set of rules S is a(x) -> a(a(x)) b(x) -> b(b(x)) We have obtained the following relative TRS: The set of rules R is a(b(x)) -> b(a(x)) The set of rules S is a(x) -> a(a(x)) b(x) -> b(b(x)) ---------------------------------------- (2) Obligation: Relative term rewrite system: The relative TRS consists of the following R rules: a(b(x)) -> b(a(x)) The relative TRS consists of the following S rules: a(x) -> a(a(x)) b(x) -> b(b(x)) ---------------------------------------- (3) RelTRSLoopFinderProof (COMPLETE) The following loop was found: ---------- Loop: ---------- a(b(x')) -> a(b(b(x'))) with rule b(x'') -> b(b(x'')) at position [0] and matcher [x'' / x'] a(b(b(x'))) -> b(a(b(x'))) with rule a(b(x)) -> b(a(x)) at position [] and matcher [x / b(x')] Now an instance of the first term with Matcher [ ] occurs in the last term at position [0]. Context: b([]) Therefore, the relative TRS problem does not terminate. ---------------------------------------- (4) NO popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to TRS Relat 75837