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TRS Relat 75837 pair #381725032
details
property
value
status
complete
benchmark
rt3-8.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n006.star.cs.uiowa.edu
space
Relative_05
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.59347200394 seconds
cpu usage
3.608613469
max memory
2.35302912E8
stage attributes
key
value
output-size
1449
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given RelTRS could be disproven: (0) RelTRS (1) RelTRSLoopFinderProof [COMPLETE, 41 ms] (2) NO ---------------------------------------- (0) Obligation: Relative term rewrite system: The relative TRS consists of the following R rules: f(s(x), y) -> f(-(s(x), y), y) The relative TRS consists of the following S rules: +(0, y) -> y +(s(x), y) -> s(+(x, y)) -(x, 0) -> x -(0, y) -> 0 -(s(x), s(y)) -> -(x, y) f(x, y) -> f(x, +(x, y)) ---------------------------------------- (1) RelTRSLoopFinderProof (COMPLETE) The following loop was found: ---------- Loop: ---------- f(-(s(x), 0), 0) -> f(s(x), 0) with rule -(x', 0) -> x' at position [0] and matcher [x' / s(x)] f(s(x), 0) -> f(-(s(x), 0), 0) with rule f(s(x'), y) -> f(-(s(x'), y), y) at position [] and matcher [x' / x, y / 0] Now an instance of the first term with Matcher [ ] occurs in the last term at position []. Context: [] Therefore, the relative TRS problem does not terminate. ---------------------------------------- (2) NO
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