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SRS Relat 19260 pair #381725223
details
property
value
status
complete
benchmark
rel13.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n112.star.cs.uiowa.edu
space
Zantema_06_relative
run statistics
property
value
solver
ttt2-1.17+nonreach
configuration
ttt2-1.17+nonreach
runtime (wallclock)
5.29914188385 seconds
cpu usage
19.976140742
max memory
1.37050112E9
stage attributes
key
value
output-size
5017
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: strict: o(l(x1)) -> r(x1) n(l(o(x1))) -> r(o(x1)) L(l(o(x1))) -> L(r(o(x1))) r(o(x1)) -> l(x1) o(r(n(x1))) -> o(l(x1)) o(r(R(x1))) -> o(l(R(x1))) weak: L(x1) -> L(n(x1)) R(x1) -> n(R(x1)) Proof: Arctic Interpretation Processor: dimension: 1 interpretation: [R](x0) = 4x0, [L](x0) = x0, [n](x0) = x0, [r](x0) = x0, [o](x0) = 1x0, [l](x0) = x0 orientation: o(l(x1)) = 1x1 >= x1 = r(x1) n(l(o(x1))) = 1x1 >= 1x1 = r(o(x1)) L(l(o(x1))) = 1x1 >= 1x1 = L(r(o(x1))) r(o(x1)) = 1x1 >= x1 = l(x1) o(r(n(x1))) = 1x1 >= 1x1 = o(l(x1)) o(r(R(x1))) = 5x1 >= 5x1 = o(l(R(x1))) L(x1) = x1 >= x1 = L(n(x1)) R(x1) = 4x1 >= 4x1 = n(R(x1)) problem: strict: n(l(o(x1))) -> r(o(x1)) L(l(o(x1))) -> L(r(o(x1))) o(r(n(x1))) -> o(l(x1)) o(r(R(x1))) -> o(l(R(x1))) weak: L(x1) -> L(n(x1)) R(x1) -> n(R(x1)) String Reversal Processor: strict: o(l(n(x1))) -> o(r(x1)) o(l(L(x1))) -> o(r(L(x1))) n(r(o(x1))) -> l(o(x1)) R(r(o(x1))) -> R(l(o(x1))) weak: L(x1) -> n(L(x1)) R(x1) -> R(n(x1)) Matrix Interpretation Processor: dim=2 interpretation: [1 2] [R](x0) = [0 2]x0, [1 0] [L](x0) = [1 0]x0, [1 0] [n](x0) = [0 0]x0, [2 0] [0] [r](x0) = [0 0]x0 + [1], [1 0] [o](x0) = [0 0]x0, [2 0] [l](x0) = [0 0]x0 orientation: [2 0] [2 0] o(l(n(x1))) = [0 0]x1 >= [0 0]x1 = o(r(x1)) [2 0] [2 0] o(l(L(x1))) = [0 0]x1 >= [0 0]x1 = o(r(L(x1))) [2 0] [2 0] n(r(o(x1))) = [0 0]x1 >= [0 0]x1 = l(o(x1)) [2 0] [2] [2 0]
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