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TRS Equat 89423 pair #381732705
details
property
value
status
complete
benchmark
AC12.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n020.star.cs.uiowa.edu
space
AProVE_AC_04
run statistics
property
value
solver
muterm 5.18
configuration
default
runtime (wallclock)
0.161936044693 seconds
cpu usage
0.159060056
max memory
4038656.0
stage attributes
key
value
output-size
7710
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x y) (THEORY (AC f)) (RULES f(g(f(h(x),x)),x) -> f(h(x),f(x,x)) f(g(g(x)),x) -> f(g(x),g(x)) f(g(h(x)),f(x,f(x,y))) -> f(g(f(h(x),y)),x) f(h(x),g(x)) -> f(g(h(x)),x) ) Problem 1: Reduction Order Processor: -> Rules: f(g(f(h(x),x)),x) -> f(h(x),f(x,x)) f(g(g(x)),x) -> f(g(x),g(x)) f(g(h(x)),f(x,f(x,y))) -> f(g(f(h(x),y)),x) f(h(x),g(x)) -> f(g(h(x)),x) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [f](X1,X2) = X1 + X2 + 2 [g](X) = X + 1 [h](X) = 2.X + 2 Problem 1: Reduction Order Processor: -> Rules: f(g(g(x)),x) -> f(g(x),g(x)) f(g(h(x)),f(x,f(x,y))) -> f(g(f(h(x),y)),x) f(h(x),g(x)) -> f(g(h(x)),x) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [f](X1,X2) = X1 + X2 + 1 [g](X) = X + 1 [h](X) = 2.X Problem 1: Reduction Order Processor: -> Rules: f(g(g(x)),x) -> f(g(x),g(x)) f(h(x),g(x)) -> f(g(h(x)),x) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [f](X1,X2) = X1 + X2 + 1 [g](X) = 2.X + 2 [h](X) = X Problem 1: Dependency Pairs Processor: -> FAxioms: F(f(x2,x3),x4) = F(x2,f(x3,x4)) F(x2,x3) = F(x3,x2) -> Pairs: F(f(h(x),g(x)),x2) -> F(f(g(h(x)),x),x2) F(f(h(x),g(x)),x2) -> F(g(h(x)),x) F(h(x),g(x)) -> F(g(h(x)),x) -> EAxioms: f(f(x2,x3),x4) = f(x2,f(x3,x4)) f(x2,x3) = f(x3,x2) -> Rules: f(h(x),g(x)) -> f(g(h(x)),x) -> SRules: F(f(x2,x3),x4) -> F(x2,x3)
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