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TRS Equat 89423 pair #381732722
details
property
value
status
complete
benchmark
YWHM14_3.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n047.star.cs.uiowa.edu
space
Mixed_AC
run statistics
property
value
solver
muterm 5.18
configuration
default
runtime (wallclock)
0.240864038467 seconds
cpu usage
0.228958485
max memory
3989504.0
stage attributes
key
value
output-size
10235
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x y) (THEORY (AC plus)) (RULES f(plus(x,y)) -> plus(f(x),y) h(a,b) -> h(b,a) h(a,g(g(a))) -> h(g(a),f(a)) h(g(a),a) -> h(a,g(b)) h(g(a),b) -> h(a,g(a)) plus(f(a),g(b)) -> plus(f(b),g(a)) plus(g(x),y) -> g(plus(x,y)) ) Problem 1: Reduction Order Processor: -> Rules: f(plus(x,y)) -> plus(f(x),y) h(a,b) -> h(b,a) h(a,g(g(a))) -> h(g(a),f(a)) h(g(a),a) -> h(a,g(b)) h(g(a),b) -> h(a,g(a)) plus(f(a),g(b)) -> plus(f(b),g(a)) plus(g(x),y) -> g(plus(x,y)) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [f](X) = 2.X [h](X1,X2) = 2.X1 + 2.X2 [plus](X1,X2) = X1 + X2 + 1 [a] = 1 [b] = 1 [g](X) = X + 2 Problem 1: Reduction Order Processor: -> Rules: h(a,b) -> h(b,a) h(a,g(g(a))) -> h(g(a),f(a)) h(g(a),a) -> h(a,g(b)) h(g(a),b) -> h(a,g(a)) plus(f(a),g(b)) -> plus(f(b),g(a)) plus(g(x),y) -> g(plus(x,y)) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [f](X) = X [h](X1,X2) = 2.X1 + X2 [plus](X1,X2) = X1 + X2 + 1 [a] = 2 [b] = 1 [g](X) = X + 2 Problem 1: Reduction Order Processor: -> Rules: h(a,g(g(a))) -> h(g(a),f(a)) h(g(a),a) -> h(a,g(b)) h(g(a),b) -> h(a,g(a)) plus(f(a),g(b)) -> plus(f(b),g(a)) plus(g(x),y) -> g(plus(x,y)) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [f](X) = 2.X [h](X1,X2) = 2.X1 + 2.X2 [plus](X1,X2) = X1 + X2
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