TRS Equat 89423 pair #381732730

details

property	value
status	complete
benchmark	AC02.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n094.star.cs.uiowa.edu
space	AProVE_AC_04

run statistics

property	value
solver	muterm 5.18
configuration	default
runtime (wallclock)	0.187636137009 seconds
cpu usage	0.168902124
max memory	3895296.0

stage attributes

key	value
output-size	8316
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

Problem 1: 

(VAR x y)
(THEORY 
(AC plus))
(RULES
double(x) -> plus(x,x)
plus(x,0) -> x
plus(x,s(y)) -> s(plus(x,y))
)

Problem 1: 

Reduction Order Processor:
-> Rules:
 double(x) -> plus(x,x)
 plus(x,0) -> x
 plus(x,s(y)) -> s(plus(x,y))
->Interpretation type:
 Linear
->Coefficients:
 Natural Numbers
->Dimension:
 1
->Bound:
 2
->Interpretation:
 
[double](X) = 2.X + 2
[plus](X1,X2) = X1 + X2
[0] = 0
[s](X) = X + 2

Problem 1: 

Reduction Order Processor:
-> Rules:
 plus(x,0) -> x
 plus(x,s(y)) -> s(plus(x,y))
->Interpretation type:
 Linear
->Coefficients:
 Natural Numbers
->Dimension:
 1
->Bound:
 2
->Interpretation:
 
[double](X) = 2.X
[plus](X1,X2) = X1 + X2 + 2
[0] = 2
[s](X) = X + 1

Problem 1: 

Dependency Pairs Processor:
-> FAxioms:
 PLUS(plus(x2,x3),x4) = PLUS(x2,plus(x3,x4))
 PLUS(x2,x3) = PLUS(x3,x2)
-> Pairs:
 PLUS(plus(x,s(y)),x2) -> PLUS(s(plus(x,y)),x2)
 PLUS(plus(x,s(y)),x2) -> PLUS(x,y)
 PLUS(x,s(y)) -> PLUS(x,y)
-> EAxioms:
 plus(plus(x2,x3),x4) = plus(x2,plus(x3,x4))
 plus(x2,x3) = plus(x3,x2)
-> Rules:
 plus(x,s(y)) -> s(plus(x,y))
-> SRules:
 PLUS(plus(x2,x3),x4) -> PLUS(x2,x3)
 PLUS(x2,plus(x3,x4)) -> PLUS(x3,x4)

Problem 1: 

SCC Processor:
-> FAxioms:
 PLUS(plus(x2,x3),x4) = PLUS(x2,plus(x3,x4))
 PLUS(x2,x3) = PLUS(x3,x2)
-> Pairs:
 PLUS(plus(x,s(y)),x2) -> PLUS(s(plus(x,y)),x2)
 PLUS(plus(x,s(y)),x2) -> PLUS(x,y)
 PLUS(x,s(y)) -> PLUS(x,y)
-> EAxioms:
 plus(plus(x2,x3),x4) = plus(x2,plus(x3,x4))
 plus(x2,x3) = plus(x3,x2)
-> Rules:
 plus(x,s(y)) -> s(plus(x,y))
-> SRules:
 PLUS(plus(x2,x3),x4) -> PLUS(x2,x3)
 PLUS(x2,plus(x3,x4)) -> PLUS(x3,x4)
->Strongly Connected Components:

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