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TRS Equat 89423 pair #381732796
details
property
value
status
complete
benchmark
AC07.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n113.star.cs.uiowa.edu
space
AProVE_AC_04
run statistics
property
value
solver
muterm 5.18
configuration
default
runtime (wallclock)
0.706593036652 seconds
cpu usage
0.560647969
max memory
4505600.0
stage attributes
key
value
output-size
21044
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x xs y) (THEORY (AC plus)) (RULES S(cons(x,xs)) -> plus(x,S(xs)) S(nil) -> 0 int(0,0) -> cons(0,nil) int(0,s(y)) -> cons(0,int(s(0),s(y))) int(s(x),0) -> nil int(s(x),s(y)) -> intlist(int(x,y)) intlist(cons(x,y)) -> cons(s(x),intlist(y)) intlist(nil) -> nil plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) sum(x,y) -> S(int(x,y)) ) Problem 1: Reduction Order Processor: -> Rules: S(cons(x,xs)) -> plus(x,S(xs)) S(nil) -> 0 int(0,0) -> cons(0,nil) int(0,s(y)) -> cons(0,int(s(0),s(y))) int(s(x),0) -> nil int(s(x),s(y)) -> intlist(int(x,y)) intlist(cons(x,y)) -> cons(s(x),intlist(y)) intlist(nil) -> nil plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) sum(x,y) -> S(int(x,y)) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [S](X) = X [int](X1,X2) = 2.X1 + 2.X2 + 2 [intlist](X) = X [plus](X1,X2) = X1 + X2 [sum](X1,X2) = 2.X1 + 2.X2 + 2 [0] = 0 [cons](X1,X2) = 2.X1 + X2 [nil] = 2 [s](X) = X Problem 1: Reduction Order Processor: -> Rules: S(cons(x,xs)) -> plus(x,S(xs)) int(0,0) -> cons(0,nil) int(0,s(y)) -> cons(0,int(s(0),s(y))) int(s(x),0) -> nil int(s(x),s(y)) -> intlist(int(x,y)) intlist(cons(x,y)) -> cons(s(x),intlist(y)) intlist(nil) -> nil plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) sum(x,y) -> S(int(x,y)) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [S](X) = X + 1 [int](X1,X2) = 2.X1 + 2.X2 + 1 [intlist](X) = X [plus](X1,X2) = X1 + X2 [sum](X1,X2) = 2.X1 + 2.X2 + 2 [0] = 0 [cons](X1,X2) = 2.X1 + X2 [nil] = 0 [s](X) = X Problem 1: Reduction Order Processor: -> Rules:
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