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TRS Condi 20667 pair #381733066
details
property
value
status
complete
benchmark
plus1.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n003.star.cs.uiowa.edu
space
Mixed_CTRS_2014
run statistics
property
value
solver
muterm 5.18
configuration
default
runtime (wallclock)
0.016529083252 seconds
cpu usage
0.013257065
max memory
1495040.0
stage attributes
key
value
output-size
1958
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x y z) (RULES plus(0,x) -> x plus(s(x),y) -> s(z) | plus(x,y) -> z plus(x,0) -> x ) Problem 1: Valid CTRS Processor: -> Rules: plus(0,x) -> x plus(s(x),y) -> s(z) | plus(x,y) -> z plus(x,0) -> x -> The system is a deterministic 3-CTRS. Problem 1: Dependency Pairs Processor: Conditional Termination Problem 1: -> Pairs: Empty -> QPairs: Empty -> Rules: plus(0,x) -> x plus(s(x),y) -> s(z) | plus(x,y) -> z plus(x,0) -> x Conditional Termination Problem 2: -> Pairs: PLUS(s(x),y) -> PLUS(x,y) -> QPairs: Empty -> Rules: plus(0,x) -> x plus(s(x),y) -> s(z) | plus(x,y) -> z plus(x,0) -> x The problem is decomposed in 2 subproblems. Problem 1.1: SCC Processor: -> Pairs: Empty -> QPairs: Empty -> Rules: plus(0,x) -> x plus(s(x),y) -> s(z) | plus(x,y) -> z plus(x,0) -> x ->Strongly Connected Components: There is no strongly connected component The problem is finite. Problem 1.2: SCC Processor: -> Pairs: PLUS(s(x),y) -> PLUS(x,y) -> QPairs: Empty -> Rules: plus(0,x) -> x plus(s(x),y) -> s(z) | plus(x,y) -> z plus(x,0) -> x ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: PLUS(s(x),y) -> PLUS(x,y) ->->-> Rules: plus(0,x) -> x plus(s(x),y) -> s(z) | plus(x,y) -> z plus(x,0) -> x Problem 1.2: Conditional Subterm Processor: -> Pairs: PLUS(s(x),y) -> PLUS(x,y) -> QPairs: Empty -> Rules: plus(0,x) -> x plus(s(x),y) -> s(z) | plus(x,y) -> z plus(x,0) -> x ->Projection:
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