details

property	value
status	complete
benchmark	#4.30a.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n089.star.cs.uiowa.edu
space	AG01_innermost

run statistics

property	value
solver	muterm 5.18
configuration	default
runtime (wallclock)	0.216957092285 seconds
cpu usage	0.144384518
max memory	4825088.0

stage attributes

key	value
output-size	5244
starexec-result	YES

output

/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x y) (RULES le(0,y) -> true le(s(x),0) -> false le(s(x),s(y)) -> le(x,y) minus(s(x),s(y)) -> minus(x,y) minus(x,0) -> x quot(0,s(y)) -> 0 quot(s(x),s(y)) -> s(quot(minus(s(x),s(y)),s(y))) ) (STRATEGY INNERMOST) Problem 1: Dependency Pairs Processor: -> Pairs: LE(s(x),s(y)) -> LE(x,y) MINUS(s(x),s(y)) -> MINUS(x,y) QUOT(s(x),s(y)) -> MINUS(s(x),s(y)) QUOT(s(x),s(y)) -> QUOT(minus(s(x),s(y)),s(y)) -> Rules: le(0,y) -> true le(s(x),0) -> false le(s(x),s(y)) -> le(x,y) minus(s(x),s(y)) -> minus(x,y) minus(x,0) -> x quot(0,s(y)) -> 0 quot(s(x),s(y)) -> s(quot(minus(s(x),s(y)),s(y))) Problem 1: SCC Processor: -> Pairs: LE(s(x),s(y)) -> LE(x,y) MINUS(s(x),s(y)) -> MINUS(x,y) QUOT(s(x),s(y)) -> MINUS(s(x),s(y)) QUOT(s(x),s(y)) -> QUOT(minus(s(x),s(y)),s(y)) -> Rules: le(0,y) -> true le(s(x),0) -> false le(s(x),s(y)) -> le(x,y) minus(s(x),s(y)) -> minus(x,y) minus(x,0) -> x quot(0,s(y)) -> 0 quot(s(x),s(y)) -> s(quot(minus(s(x),s(y)),s(y))) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: MINUS(s(x),s(y)) -> MINUS(x,y) ->->-> Rules: le(0,y) -> true le(s(x),0) -> false le(s(x),s(y)) -> le(x,y) minus(s(x),s(y)) -> minus(x,y) minus(x,0) -> x quot(0,s(y)) -> 0 quot(s(x),s(y)) -> s(quot(minus(s(x),s(y)),s(y))) ->->Cycle: ->->-> Pairs: QUOT(s(x),s(y)) -> QUOT(minus(s(x),s(y)),s(y)) ->->-> Rules: le(0,y) -> true le(s(x),0) -> false le(s(x),s(y)) -> le(x,y) minus(s(x),s(y)) -> minus(x,y) minus(x,0) -> x quot(0,s(y)) -> 0 quot(s(x),s(y)) -> s(quot(minus(s(x),s(y)),s(y))) ->->Cycle: ->->-> Pairs: LE(s(x),s(y)) -> LE(x,y) ->->-> Rules: le(0,y) -> true le(s(x),0) -> false le(s(x),s(y)) -> le(x,y) minus(s(x),s(y)) -> minus(x,y) minus(x,0) -> x quot(0,s(y)) -> 0 quot(s(x),s(y)) -> s(quot(minus(s(x),s(y)),s(y))) The problem is decomposed in 3 subproblems. Problem 1.1: Subterm Processor: -> Pairs: MINUS(s(x),s(y)) -> MINUS(x,y) -> Rules: le(0,y) -> true popout

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job log

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actions

all output return to TRS Inner 89993