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TRS Inner 89993 pair #381734059
details
property
value
status
complete
benchmark
Ex49_GM04_GM.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n053.star.cs.uiowa.edu
space
Transformed_CSR_innermost_04
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.72380185127 seconds
cpu usage
7.722729841
max memory
4.79105024E8
stage attributes
key
value
output-size
17346
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 0 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 0 ms] (4) AND (5) QDP (6) UsableRulesProof [EQUIVALENT, 0 ms] (7) QDP (8) QReductionProof [EQUIVALENT, 0 ms] (9) QDP (10) QDPSizeChangeProof [EQUIVALENT, 0 ms] (11) YES (12) QDP (13) UsableRulesProof [EQUIVALENT, 0 ms] (14) QDP (15) QReductionProof [EQUIVALENT, 0 ms] (16) QDP (17) QDPSizeChangeProof [EQUIVALENT, 0 ms] (18) YES (19) QDP (20) QDPQMonotonicMRRProof [EQUIVALENT, 73 ms] (21) QDP (22) QDPQMonotonicMRRProof [EQUIVALENT, 46 ms] (23) QDP (24) DependencyGraphProof [EQUIVALENT, 0 ms] (25) TRUE ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a__minus(0, Y) -> 0 a__minus(s(X), s(Y)) -> a__minus(X, Y) a__geq(X, 0) -> true a__geq(0, s(Y)) -> false a__geq(s(X), s(Y)) -> a__geq(X, Y) a__div(0, s(Y)) -> 0 a__div(s(X), s(Y)) -> a__if(a__geq(X, Y), s(div(minus(X, Y), s(Y))), 0) a__if(true, X, Y) -> mark(X) a__if(false, X, Y) -> mark(Y) mark(minus(X1, X2)) -> a__minus(X1, X2) mark(geq(X1, X2)) -> a__geq(X1, X2) mark(div(X1, X2)) -> a__div(mark(X1), X2) mark(if(X1, X2, X3)) -> a__if(mark(X1), X2, X3) mark(0) -> 0 mark(s(X)) -> s(mark(X)) mark(true) -> true mark(false) -> false a__minus(X1, X2) -> minus(X1, X2) a__geq(X1, X2) -> geq(X1, X2) a__div(X1, X2) -> div(X1, X2) a__if(X1, X2, X3) -> if(X1, X2, X3) The set Q consists of the following terms: mark(minus(x0, x1)) mark(geq(x0, x1)) mark(div(x0, x1)) mark(if(x0, x1, x2)) mark(0) mark(s(x0)) mark(true) mark(false) a__minus(x0, x1) a__geq(x0, x1) a__div(x0, x1) a__if(x0, x1, x2) ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: A__MINUS(s(X), s(Y)) -> A__MINUS(X, Y) A__GEQ(s(X), s(Y)) -> A__GEQ(X, Y) A__DIV(s(X), s(Y)) -> A__IF(a__geq(X, Y), s(div(minus(X, Y), s(Y))), 0)
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