details

property	value
status	complete
benchmark	PEANO_nosorts_iGM.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n085.star.cs.uiowa.edu
space	Transformed_CSR_innermost_04

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	2.18540406227 seconds
cpu usage	5.102813827
max memory	3.282944E8

stage attributes

key	value
output-size	11966
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 101 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 0 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 14 ms] (6) QTRS (7) QTRSRRRProof [EQUIVALENT, 14 ms] (8) QTRS (9) QTRSRRRProof [EQUIVALENT, 0 ms] (10) QTRS (11) QTRSRRRProof [EQUIVALENT, 6 ms] (12) QTRS (13) QTRSRRRProof [EQUIVALENT, 1 ms] (14) QTRS (15) RisEmptyProof [EQUIVALENT, 4 ms] (16) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: active(and(tt, X)) -> mark(X) active(plus(N, 0)) -> mark(N) active(plus(N, s(M))) -> mark(s(plus(N, M))) mark(and(X1, X2)) -> active(and(mark(X1), X2)) mark(tt) -> active(tt) mark(plus(X1, X2)) -> active(plus(mark(X1), mark(X2))) mark(0) -> active(0) mark(s(X)) -> active(s(mark(X))) and(mark(X1), X2) -> and(X1, X2) and(X1, mark(X2)) -> and(X1, X2) and(active(X1), X2) -> and(X1, X2) and(X1, active(X2)) -> and(X1, X2) plus(mark(X1), X2) -> plus(X1, X2) plus(X1, mark(X2)) -> plus(X1, X2) plus(active(X1), X2) -> plus(X1, X2) plus(X1, active(X2)) -> plus(X1, X2) s(mark(X)) -> s(X) s(active(X)) -> s(X) The set Q consists of the following terms: active(and(tt, x0)) active(plus(x0, 0)) active(plus(x0, s(x1))) mark(and(x0, x1)) mark(tt) mark(plus(x0, x1)) mark(0) mark(s(x0)) and(mark(x0), x1) and(x0, mark(x1)) and(active(x0), x1) and(x0, active(x1)) plus(mark(x0), x1) plus(x0, mark(x1)) plus(active(x0), x1) plus(x0, active(x1)) s(mark(x0)) s(active(x0)) ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(0) = 1 POL(active(x_1)) = x_1 POL(and(x_1, x_2)) = x_1 + x_2 POL(mark(x_1)) = x_1 POL(plus(x_1, x_2)) = x_1 + x_2 POL(s(x_1)) = x_1 POL(tt) = 0 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: active(plus(N, 0)) -> mark(N) popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to TRS Inner 89993