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C Integ Progr 58257 pair #381736324
details
property
value
status
complete
benchmark
svcomp_ex1.c
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n036.star.cs.uiowa.edu
space
Stroeder_15
run statistics
property
value
solver
AProVE
configuration
c
runtime (wallclock)
1.95118808746 seconds
cpu usage
4.99461156
max memory
3.94756096E8
stage attributes
key
value
output-size
2834
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_c /export/starexec/sandbox2/benchmark/theBenchmark.c /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.c # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given C Problem could be proven: (0) C Problem (1) CToIRSProof [EQUIVALENT, 0 ms] (2) IntTRS (3) TerminationGraphProcessor [SOUND, 54 ms] (4) IntTRS (5) IntTRSCompressionProof [EQUIVALENT, 0 ms] (6) IntTRS (7) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] (8) IntTRS (9) RankingReductionPairProof [EQUIVALENT, 19 ms] (10) YES ---------------------------------------- (0) Obligation: c file /export/starexec/sandbox2/benchmark/theBenchmark.c ---------------------------------------- (1) CToIRSProof (EQUIVALENT) Parsed C Integer Program as IRS. ---------------------------------------- (2) Obligation: Rules: f1(x, y, r) -> f2(x_1, y, r) :|: TRUE f2(x1, x2, x3) -> f3(x1, x4, x3) :|: TRUE f3(x5, x6, x7) -> f4(x5, x6, 1) :|: TRUE f5(x8, x9, x10) -> f6(x8, x9, arith) :|: TRUE && arith = x10 * x8 f6(x23, x24, x25) -> f7(x23, x26, x25) :|: TRUE && x26 = x24 - 1 f4(x14, x15, x16) -> f5(x14, x15, x16) :|: x15 > 0 f7(x17, x18, x19) -> f4(x17, x18, x19) :|: TRUE f4(x20, x21, x22) -> f8(x20, x21, x22) :|: x21 <= 0 Start term: f1(x, y, r) ---------------------------------------- (3) TerminationGraphProcessor (SOUND) Constructed the termination graph and obtained one non-trivial SCC. ---------------------------------------- (4) Obligation: Rules: f4(x14, x15, x16) -> f5(x14, x15, x16) :|: x15 > 0 f7(x17, x18, x19) -> f4(x17, x18, x19) :|: TRUE f6(x23, x24, x25) -> f7(x23, x26, x25) :|: TRUE && x26 = x24 - 1 f5(x8, x9, x10) -> f6(x8, x9, arith) :|: TRUE && arith = x10 * x8 ---------------------------------------- (5) IntTRSCompressionProof (EQUIVALENT) Compressed rules. ---------------------------------------- (6) Obligation: Rules: f6(x23:0, x24:0, x25:0) -> f6(x23:0, x24:0 - 1, x25:0 * x23:0) :|: x24:0 > 1 ---------------------------------------- (7) IntTRSUnneededArgumentFilterProof (EQUIVALENT) Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: f6(x1, x2, x3) -> f6(x2) ---------------------------------------- (8) Obligation: Rules: f6(x24:0) -> f6(x24:0 - 1) :|: x24:0 > 1 ---------------------------------------- (9) RankingReductionPairProof (EQUIVALENT) Interpretation: [ f6 ] = f6_1 The following rules are decreasing: f6(x24:0) -> f6(x24:0 - 1) :|: x24:0 > 1 The following rules are bounded:
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