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C Integ Progr 58257 pair #381736417
details
property
value
status
complete
benchmark
Et1.c
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n089.star.cs.uiowa.edu
space
Stroeder_15
run statistics
property
value
solver
AProVE
configuration
c
runtime (wallclock)
2.45853590965 seconds
cpu usage
6.643215078
max memory
3.13413632E8
stage attributes
key
value
output-size
4687
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_c /export/starexec/sandbox/benchmark/theBenchmark.c /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.c # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given C Problem could be proven: (0) C Problem (1) CToIRSProof [EQUIVALENT, 0 ms] (2) IntTRS (3) TerminationGraphProcessor [SOUND, 27 ms] (4) IntTRS (5) IntTRSCompressionProof [EQUIVALENT, 16 ms] (6) IntTRS (7) TerminationGraphProcessor [EQUIVALENT, 23 ms] (8) IntTRS (9) IntTRSCompressionProof [EQUIVALENT, 0 ms] (10) IntTRS (11) PolynomialOrderProcessor [EQUIVALENT, 0 ms] (12) YES ---------------------------------------- (0) Obligation: c file /export/starexec/sandbox/benchmark/theBenchmark.c ---------------------------------------- (1) CToIRSProof (EQUIVALENT) Parsed C Integer Program as IRS. ---------------------------------------- (2) Obligation: Rules: f1(a, b) -> f2(arith, b) :|: TRUE && arith = 0 - x_1 f2(x13, x14) -> f3(x13, x15) :|: TRUE && x15 = 0 - x16 f4(x17, x18) -> f5(x17, x19) :|: TRUE && x19 = x18 + x17 f5(x20, x21) -> f6(x22, x21) :|: TRUE && x22 = x20 + 1 f3(x7, x8) -> f4(x7, x8) :|: x7 > x8 f6(x9, x10) -> f3(x9, x10) :|: TRUE f3(x11, x12) -> f7(x11, x12) :|: x11 <= x12 Start term: f1(a, b) ---------------------------------------- (3) TerminationGraphProcessor (SOUND) Constructed the termination graph and obtained one non-trivial SCC. ---------------------------------------- (4) Obligation: Rules: f3(x7, x8) -> f4(x7, x8) :|: x7 > x8 f6(x9, x10) -> f3(x9, x10) :|: TRUE f5(x20, x21) -> f6(x22, x21) :|: TRUE && x22 = x20 + 1 f4(x17, x18) -> f5(x17, x19) :|: TRUE && x19 = x18 + x17 ---------------------------------------- (5) IntTRSCompressionProof (EQUIVALENT) Compressed rules. ---------------------------------------- (6) Obligation: Rules: f5(x20:0, x21:0) -> f5(x20:0 + 1, x21:0 + (x20:0 + 1)) :|: x21:0 < x20:0 + 1 ---------------------------------------- (7) TerminationGraphProcessor (EQUIVALENT) Constructed the termination graph and obtained one non-trivial SCC. f5(x20:0, x21:0) -> f5(x20:0 + 1, x21:0 + (x20:0 + 1)) :|: x21:0 < x20:0 + 1 has been transformed into f5(x20:0, x21:0) -> f5(x20:0 + 1, x21:0 + (x20:0 + 1)) :|: x21:0 = x5 + (x4 + 1) && (x20:0 = x4 + 1 && x21:0 < x20:0 + 1) && x5 < x4 + 1. f5(x20:0, x21:0) -> f5(x20:0 + 1, x21:0 + (x20:0 + 1)) :|: x21:0 = x5 + (x4 + 1) && (x20:0 = x4 + 1 && x21:0 < x20:0 + 1) && x5 < x4 + 1 and f5(x20:0, x21:0) -> f5(x20:0 + 1, x21:0 + (x20:0 + 1)) :|: x21:0 = x5 + (x4 + 1) && (x20:0 = x4 + 1 && x21:0 < x20:0 + 1) && x5 < x4 + 1 have been merged into the new rule f5(x14, x15) -> f5(x14 + 1 + 1, x15 + (x14 + 1) + (x14 + 1 + 1)) :|: x15 = x16 + (x17 + 1) && (x14 = x17 + 1 && x15 < x14 + 1) && x16 < x17 + 1 && (x15 + (x14 + 1) = x18 + (x19 + 1) && (x14 + 1 = x19 + 1 && x15 + (x14 + 1) < x14 + 1 + 1) && x18 < x19 + 1) ---------------------------------------- (8) Obligation: Rules: f5(x20, x21) -> f5(x20 + 2, x21 + 2 * x20 + 3) :|: TRUE && x21 + -1 * x22 + -1 * x23 = 1 && x20 + -1 * x23 = 1 && x21 + -1 * x20 <= 0 && x22 + -1 * x23 <= 0 && x21 + x20 + -1 * x24 + -1 * x25 = 0 && x20 + -1 * x25 = 0 && x21 <= 0 && x24 + -1 * x25 <= 0
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