details

property	value
status	complete
benchmark	AliasDarteFeautrierGonnord-SAS2010-terminate_true-termination.c
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n027.star.cs.uiowa.edu
space	Stroeder_15

run statistics

property	value
solver	AProVE
configuration	c
runtime (wallclock)	2.0157790184 seconds
cpu usage	5.177204035
max memory	4.14715904E8

stage attributes

key	value
output-size	3571
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_c /export/starexec/sandbox2/benchmark/theBenchmark.c /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.c # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given C Problem could be proven: (0) C Problem (1) CToIRSProof [EQUIVALENT, 0 ms] (2) IntTRS (3) TerminationGraphProcessor [SOUND, 46 ms] (4) IntTRS (5) IntTRSCompressionProof [EQUIVALENT, 32 ms] (6) IntTRS (7) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] (8) IntTRS (9) PolynomialOrderProcessor [EQUIVALENT, 20 ms] (10) YES ---------------------------------------- (0) Obligation: c file /export/starexec/sandbox2/benchmark/theBenchmark.c ---------------------------------------- (1) CToIRSProof (EQUIVALENT) Parsed C Integer Program as IRS. ---------------------------------------- (2) Obligation: Rules: f1(i, j, k, ell) -> f2(x_1, j, k, ell) :|: TRUE f2(x, x1, x2, x3) -> f3(x, x4, x2, x3) :|: TRUE f3(x5, x6, x7, x8) -> f4(x5, x6, x9, x8) :|: TRUE f5(x10, x11, x12, x13) -> f6(x10, x11, x12, x10) :|: TRUE f6(x14, x15, x16, x17) -> f7(x15, x15, x16, x17) :|: TRUE f7(x18, x19, x20, x21) -> f8(x18, arith, x20, x21) :|: TRUE && arith = x21 + 1 f8(x38, x39, x40, x41) -> f9(x38, x39, x42, x41) :|: TRUE && x42 = x40 - 1 f4(x26, x27, x28, x29) -> f5(x26, x27, x28, x29) :|: x26 <= 100 && x27 <= x28 f9(x30, x31, x32, x33) -> f4(x30, x31, x32, x33) :|: TRUE f4(x34, x35, x36, x37) -> f10(x34, x35, x36, x37) :|: x34 > 100 f4(x43, x44, x45, x46) -> f10(x43, x44, x45, x46) :|: x44 > x45 Start term: f1(i, j, k, ell) ---------------------------------------- (3) TerminationGraphProcessor (SOUND) Constructed the termination graph and obtained one non-trivial SCC. ---------------------------------------- (4) Obligation: Rules: f4(x26, x27, x28, x29) -> f5(x26, x27, x28, x29) :|: x26 <= 100 && x27 <= x28 f9(x30, x31, x32, x33) -> f4(x30, x31, x32, x33) :|: TRUE f8(x38, x39, x40, x41) -> f9(x38, x39, x42, x41) :|: TRUE && x42 = x40 - 1 f7(x18, x19, x20, x21) -> f8(x18, arith, x20, x21) :|: TRUE && arith = x21 + 1 f6(x14, x15, x16, x17) -> f7(x15, x15, x16, x17) :|: TRUE f5(x10, x11, x12, x13) -> f6(x10, x11, x12, x10) :|: TRUE ---------------------------------------- (5) IntTRSCompressionProof (EQUIVALENT) Compressed rules. ---------------------------------------- (6) Obligation: Rules: f6(x14:0, x15:0, x16:0, x17:0) -> f6(x15:0, x17:0 + 1, x16:0 - 1, x15:0) :|: x15:0 < 101 && x17:0 + 1 <= x16:0 - 1 ---------------------------------------- (7) IntTRSUnneededArgumentFilterProof (EQUIVALENT) Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: f6(x1, x2, x3, x4) -> f6(x2, x3, x4) ---------------------------------------- (8) Obligation: Rules: f6(x15:0, x16:0, x17:0) -> f6(x17:0 + 1, x16:0 - 1, x15:0) :|: x15:0 < 101 && x17:0 + 1 <= x16:0 - 1 ---------------------------------------- (9) PolynomialOrderProcessor (EQUIVALENT) Found the following polynomial interpretation: [f6(x, x1, x2)] = 98 - x + x1 - x2 popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to C Integ Progr 58257