Spaces
Explore
Communities
Statistics
Reports
Cluster
Status
Help
C Integ Progr 58257 pair #381736642
details
property
value
status
complete
benchmark
Masse-VMCAI2014-Ex6_true-termination.c
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n039.star.cs.uiowa.edu
space
Stroeder_15
run statistics
property
value
solver
AProVE
configuration
c
runtime (wallclock)
2.53798604012 seconds
cpu usage
6.702397073
max memory
3.01633536E8
stage attributes
key
value
output-size
3298
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_c /export/starexec/sandbox/benchmark/theBenchmark.c /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.c # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given C Problem could be proven: (0) C Problem (1) CToIRSProof [EQUIVALENT, 0 ms] (2) IntTRS (3) TerminationGraphProcessor [SOUND, 55 ms] (4) IntTRS (5) IntTRSCompressionProof [EQUIVALENT, 41 ms] (6) IntTRS (7) PolynomialOrderProcessor [EQUIVALENT, 0 ms] (8) IntTRS (9) PolynomialOrderProcessor [EQUIVALENT, 2 ms] (10) YES ---------------------------------------- (0) Obligation: c file /export/starexec/sandbox/benchmark/theBenchmark.c ---------------------------------------- (1) CToIRSProof (EQUIVALENT) Parsed C Integer Program as IRS. ---------------------------------------- (2) Obligation: Rules: f1(x, y) -> f2(x_1, y) :|: TRUE f2(x1, x2) -> f3(x1, x3) :|: TRUE f4(x4, x5) -> f5(arith, x5) :|: TRUE && arith = x4 + x5 f6(x22, x23) -> f9(x22, x24) :|: TRUE && x24 = x23 - 1 f5(x8, x9) -> f6(x8, x9) :|: x9 >= 0 f5(x10, x11) -> f7(x10, x11) :|: x11 < 0 f9(x12, x13) -> f8(x12, x13) :|: TRUE f7(x14, x15) -> f8(x14, x15) :|: TRUE f3(x16, x17) -> f4(x16, x17) :|: x16 >= 0 f8(x18, x19) -> f3(x18, x19) :|: TRUE f3(x20, x21) -> f10(x20, x21) :|: x20 < 0 Start term: f1(x, y) ---------------------------------------- (3) TerminationGraphProcessor (SOUND) Constructed the termination graph and obtained one non-trivial SCC. ---------------------------------------- (4) Obligation: Rules: f3(x16, x17) -> f4(x16, x17) :|: x16 >= 0 f8(x18, x19) -> f3(x18, x19) :|: TRUE f9(x12, x13) -> f8(x12, x13) :|: TRUE f6(x22, x23) -> f9(x22, x24) :|: TRUE && x24 = x23 - 1 f5(x8, x9) -> f6(x8, x9) :|: x9 >= 0 f4(x4, x5) -> f5(arith, x5) :|: TRUE && arith = x4 + x5 f7(x14, x15) -> f8(x14, x15) :|: TRUE f5(x10, x11) -> f7(x10, x11) :|: x11 < 0 ---------------------------------------- (5) IntTRSCompressionProof (EQUIVALENT) Compressed rules. ---------------------------------------- (6) Obligation: Rules: f5(x10:0, x11:0) -> f5(x10:0 + x11:0, x11:0) :|: x11:0 < 0 && x10:0 > -1 f5(x8:0, x9:0) -> f5(x8:0 + (x9:0 - 1), x9:0 - 1) :|: x9:0 > -1 && x8:0 > -1 ---------------------------------------- (7) PolynomialOrderProcessor (EQUIVALENT) Found the following polynomial interpretation: [f5(x, x1)] = x1 The following rules are decreasing: f5(x8:0, x9:0) -> f5(x8:0 + (x9:0 - 1), x9:0 - 1) :|: x9:0 > -1 && x8:0 > -1 The following rules are bounded: f5(x8:0, x9:0) -> f5(x8:0 + (x9:0 - 1), x9:0 - 1) :|: x9:0 > -1 && x8:0 > -1 ---------------------------------------- (8) Obligation: Rules:
popout
output may be truncated. 'popout' for the full output.
job log
popout
actions
all output
return to C Integ Progr 58257