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C Integ Progr 58257 pair #381736792
details
property
value
status
complete
benchmark
AliasDarteFeautrierGonnord-SAS2010-exmini_true-termination.c
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n035.star.cs.uiowa.edu
space
Stroeder_15
run statistics
property
value
solver
AProVE
configuration
c
runtime (wallclock)
2.07869887352 seconds
cpu usage
5.523502192
max memory
4.31321088E8
stage attributes
key
value
output-size
3632
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_c /export/starexec/sandbox2/benchmark/theBenchmark.c /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.c # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given C Problem could be proven: (0) C Problem (1) CToIRSProof [EQUIVALENT, 0 ms] (2) IntTRS (3) TerminationGraphProcessor [SOUND, 64 ms] (4) IntTRS (5) IntTRSCompressionProof [EQUIVALENT, 11 ms] (6) IntTRS (7) IntTRSUnneededArgumentFilterProof [EQUIVALENT, 0 ms] (8) IntTRS (9) PolynomialOrderProcessor [EQUIVALENT, 0 ms] (10) YES ---------------------------------------- (0) Obligation: c file /export/starexec/sandbox2/benchmark/theBenchmark.c ---------------------------------------- (1) CToIRSProof (EQUIVALENT) Parsed C Integer Program as IRS. ---------------------------------------- (2) Obligation: Rules: f1(i, j, k, tmp) -> f2(x_1, j, k, tmp) :|: TRUE f2(x, x1, x2, x3) -> f3(x, x4, x2, x3) :|: TRUE f3(x5, x6, x7, x8) -> f4(x5, x6, x9, x8) :|: TRUE f4(x10, x11, x12, x13) -> f5(x10, x11, x12, x14) :|: TRUE f6(x15, x16, x17, x18) -> f7(x15, x16, x17, x15) :|: TRUE f7(x19, x20, x21, x22) -> f8(x20, x20, x21, x22) :|: TRUE f8(x23, x24, x25, x26) -> f9(x23, arith, x25, x26) :|: TRUE && arith = x26 + 1 f9(x43, x44, x45, x46) -> f10(x43, x44, x47, x46) :|: TRUE && x47 = x45 - 1 f5(x31, x32, x33, x34) -> f6(x31, x32, x33, x34) :|: x31 <= 100 && x32 <= x33 f10(x35, x36, x37, x38) -> f5(x35, x36, x37, x38) :|: TRUE f5(x39, x40, x41, x42) -> f11(x39, x40, x41, x42) :|: x39 > 100 f5(x48, x49, x50, x51) -> f11(x48, x49, x50, x51) :|: x49 > x50 Start term: f1(i, j, k, tmp) ---------------------------------------- (3) TerminationGraphProcessor (SOUND) Constructed the termination graph and obtained one non-trivial SCC. ---------------------------------------- (4) Obligation: Rules: f5(x31, x32, x33, x34) -> f6(x31, x32, x33, x34) :|: x31 <= 100 && x32 <= x33 f10(x35, x36, x37, x38) -> f5(x35, x36, x37, x38) :|: TRUE f9(x43, x44, x45, x46) -> f10(x43, x44, x47, x46) :|: TRUE && x47 = x45 - 1 f8(x23, x24, x25, x26) -> f9(x23, arith, x25, x26) :|: TRUE && arith = x26 + 1 f7(x19, x20, x21, x22) -> f8(x20, x20, x21, x22) :|: TRUE f6(x15, x16, x17, x18) -> f7(x15, x16, x17, x15) :|: TRUE ---------------------------------------- (5) IntTRSCompressionProof (EQUIVALENT) Compressed rules. ---------------------------------------- (6) Obligation: Rules: f7(x19:0, x20:0, x21:0, x22:0) -> f7(x20:0, x22:0 + 1, x21:0 - 1, x20:0) :|: x20:0 < 101 && x22:0 + 1 <= x21:0 - 1 ---------------------------------------- (7) IntTRSUnneededArgumentFilterProof (EQUIVALENT) Some arguments are removed because they cannot influence termination. We removed arguments according to the following replacements: f7(x1, x2, x3, x4) -> f7(x2, x3, x4) ---------------------------------------- (8) Obligation: Rules: f7(x20:0, x21:0, x22:0) -> f7(x22:0 + 1, x21:0 - 1, x20:0) :|: x20:0 < 101 && x22:0 + 1 <= x21:0 - 1 ---------------------------------------- (9) PolynomialOrderProcessor (EQUIVALENT) Found the following polynomial interpretation:
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