details

property	value
status	complete
benchmark	WhileIncrPart.c
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n093.star.cs.uiowa.edu
space	Stroeder_15

run statistics

property	value
solver	AProVE
configuration	c
runtime (wallclock)	3.43750119209 seconds
cpu usage	10.86060791
max memory	7.88893696E8

stage attributes

key	value
output-size	2467
starexec-result	NO

output

/export/starexec/sandbox2/solver/bin/starexec_run_c /export/starexec/sandbox2/benchmark/theBenchmark.c /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.c # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination of the given C Problem could be disproven: (0) C Problem (1) CToIRSProof [EQUIVALENT, 0 ms] (2) IntTRS (3) IRS2T2 [EQUIVALENT, 0 ms] (4) T2IntSys (5) T2 [COMPLETE, 1347 ms] (6) NO ---------------------------------------- (0) Obligation: c file /export/starexec/sandbox2/benchmark/theBenchmark.c ---------------------------------------- (1) CToIRSProof (EQUIVALENT) Parsed C Integer Program as IRS. ---------------------------------------- (2) Obligation: Rules: f1(i) -> f2(x_1) :|: TRUE f4(x) -> f7(arith) :|: TRUE && arith = x + 1 f5(x9) -> f8(x10) :|: TRUE && x10 = x9 - 1 f3(x2) -> f4(x2) :|: x2 > 3 f3(x3) -> f5(x3) :|: x3 <= 3 f7(x4) -> f6(x4) :|: TRUE f8(x5) -> f6(x5) :|: TRUE f2(x6) -> f3(x6) :|: x6 > 0 f6(x7) -> f2(x7) :|: TRUE f2(x8) -> f9(x8) :|: x8 <= 0 Start term: f1(i) ---------------------------------------- (3) IRS2T2 (EQUIVALENT) Transformed input IRS into an integer transition system.Used the following mapping from defined symbols to location IDs: (f1_1,1) (f2_1,2) (f4_1,3) (f7_1,4) (f5_1,5) (f8_1,6) (f3_1,7) (f6_1,8) (f9_1,9) ---------------------------------------- (4) Obligation: START: 1; FROM: 1; oldX0 := x0; oldX1 := nondet(); assume(0 = 0); x0 := oldX1; TO: 2; FROM: 3; oldX0 := x0; oldX1 := -(-(oldX0 + 1)); assume(0 = 0 && oldX1 = oldX0 + 1); x0 := -(-(oldX0 + 1)); TO: 4; FROM: 5; oldX0 := x0; oldX1 := -(1 - oldX0); assume(0 = 0 && oldX1 = oldX0 - 1); x0 := -(1 - oldX0); TO: 6; FROM: 7; oldX0 := x0; assume(oldX0 > 3); x0 := oldX0; TO: 3; FROM: 7; oldX0 := x0; assume(oldX0 <= 3); x0 := oldX0; popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to C Integ Progr 58257