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Integ Trans Syste 27634 pair #381736897
details
property
value
status
complete
benchmark
refine_disj_problem.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n038.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
2.17095899582 seconds
cpu usage
2.301236472
max memory
1.9369984E7
stage attributes
key
value
output-size
1718
starexec-result
MAYBE
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = f6#(x1, x2, x3) -> f1#(x1, x2, x3) f5#(I0, I1, I2) -> f2#(I0, I1, I2) f4#(I3, I4, I5) -> f5#(I3, I4 + I5, I5) f3#(I6, I7, I8) -> f4#(I6, I7, I8) [I6 = I6] f2#(I9, I10, I11) -> f3#(I9, I10, I11) [1 <= I10] f1#(I12, I13, I14) -> f2#(I12, I13, I14) R = f6(x1, x2, x3) -> f1(x1, x2, x3) f5(I0, I1, I2) -> f2(I0, I1, I2) f4(I3, I4, I5) -> f5(I3, I4 + I5, I5) f3(I6, I7, I8) -> f4(I6, I7, I8) [I6 = I6] f2(I9, I10, I11) -> f3(I9, I10, I11) [1 <= I10] f1(I12, I13, I14) -> f2(I12, I13, I14) The dependency graph for this problem is: 0 -> 5 1 -> 4 2 -> 1 3 -> 2 4 -> 3 5 -> 4 Where: 0) f6#(x1, x2, x3) -> f1#(x1, x2, x3) 1) f5#(I0, I1, I2) -> f2#(I0, I1, I2) 2) f4#(I3, I4, I5) -> f5#(I3, I4 + I5, I5) 3) f3#(I6, I7, I8) -> f4#(I6, I7, I8) [I6 = I6] 4) f2#(I9, I10, I11) -> f3#(I9, I10, I11) [1 <= I10] 5) f1#(I12, I13, I14) -> f2#(I12, I13, I14) We have the following SCCs. { 1, 2, 3, 4 } DP problem for innermost termination. P = f5#(I0, I1, I2) -> f2#(I0, I1, I2) f4#(I3, I4, I5) -> f5#(I3, I4 + I5, I5) f3#(I6, I7, I8) -> f4#(I6, I7, I8) [I6 = I6] f2#(I9, I10, I11) -> f3#(I9, I10, I11) [1 <= I10] R = f6(x1, x2, x3) -> f1(x1, x2, x3) f5(I0, I1, I2) -> f2(I0, I1, I2) f4(I3, I4, I5) -> f5(I3, I4 + I5, I5) f3(I6, I7, I8) -> f4(I6, I7, I8) [I6 = I6] f2(I9, I10, I11) -> f3(I9, I10, I11) [1 <= I10] f1(I12, I13, I14) -> f2(I12, I13, I14)
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