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Integ Trans Syste 27634 pair #381736975
details
property
value
status
complete
benchmark
ex33.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n035.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
0.13729095459 seconds
cpu usage
0.140253233
max memory
8675328.0
stage attributes
key
value
output-size
2124
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES DP problem for innermost termination. P = f6#(x1, x2, x3, x4, x5, x6) -> f5#(x1, x2, x3, x4, x5, x6) f5#(I0, I1, I2, I3, I4, I5) -> f4#(I0, I1, I2, rnd4, I4, rnd6) [rnd6 = rnd6 /\ rnd4 = rnd4] f4#(I6, I7, I8, I9, I10, I11) -> f3#(I6, I7, I8, I9, I10, I11) [1 + I11 <= -1] f4#(I12, I13, I14, I15, I16, I17) -> f3#(I12, I13, I14, I15, I16, I17) [0 <= I17] f4#(I18, I19, I20, I21, I22, I23) -> f1#(rnd1, 0, rnd3, I21, I22, I23) [rnd3 = rnd3 /\ rnd1 = rnd1 /\ -1 <= I23 /\ I23 <= -1] f3#(I24, I25, I26, I27, I28, I29) -> f1#(I24, I25, I26, I27, rnd5, I29) [rnd5 = rnd5] R = f6(x1, x2, x3, x4, x5, x6) -> f5(x1, x2, x3, x4, x5, x6) f5(I0, I1, I2, I3, I4, I5) -> f4(I0, I1, I2, rnd4, I4, rnd6) [rnd6 = rnd6 /\ rnd4 = rnd4] f4(I6, I7, I8, I9, I10, I11) -> f3(I6, I7, I8, I9, I10, I11) [1 + I11 <= -1] f4(I12, I13, I14, I15, I16, I17) -> f3(I12, I13, I14, I15, I16, I17) [0 <= I17] f4(I18, I19, I20, I21, I22, I23) -> f1(rnd1, 0, rnd3, I21, I22, I23) [rnd3 = rnd3 /\ rnd1 = rnd1 /\ -1 <= I23 /\ I23 <= -1] f3(I24, I25, I26, I27, I28, I29) -> f1(I24, I25, I26, I27, rnd5, I29) [rnd5 = rnd5] f1(I30, I31, I32, I33, I34, I35) -> f2(I30, I31, I32, I33, I34, I35) The dependency graph for this problem is: 0 -> 1 1 -> 2, 3, 4 2 -> 5 3 -> 5 4 -> 5 -> Where: 0) f6#(x1, x2, x3, x4, x5, x6) -> f5#(x1, x2, x3, x4, x5, x6) 1) f5#(I0, I1, I2, I3, I4, I5) -> f4#(I0, I1, I2, rnd4, I4, rnd6) [rnd6 = rnd6 /\ rnd4 = rnd4] 2) f4#(I6, I7, I8, I9, I10, I11) -> f3#(I6, I7, I8, I9, I10, I11) [1 + I11 <= -1] 3) f4#(I12, I13, I14, I15, I16, I17) -> f3#(I12, I13, I14, I15, I16, I17) [0 <= I17] 4) f4#(I18, I19, I20, I21, I22, I23) -> f1#(rnd1, 0, rnd3, I21, I22, I23) [rnd3 = rnd3 /\ rnd1 = rnd1 /\ -1 <= I23 /\ I23 <= -1] 5) f3#(I24, I25, I26, I27, I28, I29) -> f1#(I24, I25, I26, I27, rnd5, I29) [rnd5 = rnd5] We have the following SCCs.
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