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Integ Trans Syste 27634 pair #381736993
details
property
value
status
complete
benchmark
java_Double2.c.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n052.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
12.4021749496 seconds
cpu usage
13.045035798
max memory
2.6996736E7
stage attributes
key
value
output-size
8267
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES DP problem for innermost termination. P = f9#(x1, x2, x3, x4, x5, x6) -> f7#(x1, x2, x3, x4, x5, x6) f7#(I0, I1, I2, I3, I4, I5) -> f5#(I0, I1, I2, I3, I4, I5) f7#(I6, I7, I8, I9, I10, I11) -> f6#(I6, I7, I8, I9, I10, I11) f7#(I12, I13, I14, I15, I16, I17) -> f4#(I12, I13, I14, I15, I16, I17) f7#(I18, I19, I20, I21, I22, I23) -> f3#(I18, I19, I20, I21, I22, I23) f7#(I24, I25, I26, I27, I28, I29) -> f1#(I24, I25, I26, I27, I28, I29) f5#(I48, I49, I50, I51, I52, I53) -> f6#(I52, I53, I54, I51, I52, I55) [I55 = I54 /\ I54 = I54] f6#(I56, I57, I58, I59, I60, I61) -> f4#(I60, I61, I58, I59, I60, -1 + I60) f4#(I62, I63, I64, I65, I66, I67) -> f3#(I66, I67, I64, I65, I66, I67) [0 <= I67] f4#(I68, I69, I70, I71, I72, I73) -> f1#(I72, I73, I70, I71, I72, I73) [1 + I73 <= 0] f3#(I74, I75, I76, I77, I78, I79) -> f5#(I78, I79, I80, I77, I79, I81) [I81 = I80 /\ I80 = I80] f3#(I82, I83, I84, I85, I86, I87) -> f4#(I86, I87, I84, I85, I86, -1 + I87) R = f9(x1, x2, x3, x4, x5, x6) -> f7(x1, x2, x3, x4, x5, x6) f7(I0, I1, I2, I3, I4, I5) -> f5(I0, I1, I2, I3, I4, I5) f7(I6, I7, I8, I9, I10, I11) -> f6(I6, I7, I8, I9, I10, I11) f7(I12, I13, I14, I15, I16, I17) -> f4(I12, I13, I14, I15, I16, I17) f7(I18, I19, I20, I21, I22, I23) -> f3(I18, I19, I20, I21, I22, I23) f7(I24, I25, I26, I27, I28, I29) -> f1(I24, I25, I26, I27, I28, I29) f7(I30, I31, I32, I33, I34, I35) -> f2(I30, I31, I32, I33, I34, I35) f7(I36, I37, I38, I39, I40, I41) -> f8(I36, I37, I38, I39, I40, I41) f7(I42, I43, I44, I45, I46, I47) -> f8(I46, I47, rnd3, rnd4, rnd5, rnd6) [rnd6 = rnd4 /\ rnd5 = rnd3 /\ rnd4 = rnd4 /\ rnd3 = rnd3] f5(I48, I49, I50, I51, I52, I53) -> f6(I52, I53, I54, I51, I52, I55) [I55 = I54 /\ I54 = I54] f6(I56, I57, I58, I59, I60, I61) -> f4(I60, I61, I58, I59, I60, -1 + I60) f4(I62, I63, I64, I65, I66, I67) -> f3(I66, I67, I64, I65, I66, I67) [0 <= I67] f4(I68, I69, I70, I71, I72, I73) -> f1(I72, I73, I70, I71, I72, I73) [1 + I73 <= 0] f3(I74, I75, I76, I77, I78, I79) -> f5(I78, I79, I80, I77, I79, I81) [I81 = I80 /\ I80 = I80] f3(I82, I83, I84, I85, I86, I87) -> f4(I86, I87, I84, I85, I86, -1 + I87) f1(I88, I89, I90, I91, I92, I93) -> f2(I92, I93, I94, I95, I96, I97) [I97 = I95 /\ I96 = I94 /\ I95 = I95 /\ I94 = I94] The dependency graph for this problem is: 0 -> 1, 2, 3, 4, 5 1 -> 6 2 -> 7 3 -> 8, 9 4 -> 10, 11 5 -> 6 -> 7 7 -> 8, 9 8 -> 10, 11 9 -> 10 -> 6 11 -> 8, 9 Where: 0) f9#(x1, x2, x3, x4, x5, x6) -> f7#(x1, x2, x3, x4, x5, x6) 1) f7#(I0, I1, I2, I3, I4, I5) -> f5#(I0, I1, I2, I3, I4, I5) 2) f7#(I6, I7, I8, I9, I10, I11) -> f6#(I6, I7, I8, I9, I10, I11) 3) f7#(I12, I13, I14, I15, I16, I17) -> f4#(I12, I13, I14, I15, I16, I17) 4) f7#(I18, I19, I20, I21, I22, I23) -> f3#(I18, I19, I20, I21, I22, I23) 5) f7#(I24, I25, I26, I27, I28, I29) -> f1#(I24, I25, I26, I27, I28, I29) 6) f5#(I48, I49, I50, I51, I52, I53) -> f6#(I52, I53, I54, I51, I52, I55) [I55 = I54 /\ I54 = I54] 7) f6#(I56, I57, I58, I59, I60, I61) -> f4#(I60, I61, I58, I59, I60, -1 + I60) 8) f4#(I62, I63, I64, I65, I66, I67) -> f3#(I66, I67, I64, I65, I66, I67) [0 <= I67] 9) f4#(I68, I69, I70, I71, I72, I73) -> f1#(I72, I73, I70, I71, I72, I73) [1 + I73 <= 0] 10) f3#(I74, I75, I76, I77, I78, I79) -> f5#(I78, I79, I80, I77, I79, I81) [I81 = I80 /\ I80 = I80] 11) f3#(I82, I83, I84, I85, I86, I87) -> f4#(I86, I87, I84, I85, I86, -1 + I87) We have the following SCCs. { 6, 7, 8, 10, 11 } DP problem for innermost termination. P = f5#(I48, I49, I50, I51, I52, I53) -> f6#(I52, I53, I54, I51, I52, I55) [I55 = I54 /\ I54 = I54] f6#(I56, I57, I58, I59, I60, I61) -> f4#(I60, I61, I58, I59, I60, -1 + I60) f4#(I62, I63, I64, I65, I66, I67) -> f3#(I66, I67, I64, I65, I66, I67) [0 <= I67] f3#(I74, I75, I76, I77, I78, I79) -> f5#(I78, I79, I80, I77, I79, I81) [I81 = I80 /\ I80 = I80] f3#(I82, I83, I84, I85, I86, I87) -> f4#(I86, I87, I84, I85, I86, -1 + I87) R = f9(x1, x2, x3, x4, x5, x6) -> f7(x1, x2, x3, x4, x5, x6) f7(I0, I1, I2, I3, I4, I5) -> f5(I0, I1, I2, I3, I4, I5) f7(I6, I7, I8, I9, I10, I11) -> f6(I6, I7, I8, I9, I10, I11) f7(I12, I13, I14, I15, I16, I17) -> f4(I12, I13, I14, I15, I16, I17) f7(I18, I19, I20, I21, I22, I23) -> f3(I18, I19, I20, I21, I22, I23) f7(I24, I25, I26, I27, I28, I29) -> f1(I24, I25, I26, I27, I28, I29) f7(I30, I31, I32, I33, I34, I35) -> f2(I30, I31, I32, I33, I34, I35) f7(I36, I37, I38, I39, I40, I41) -> f8(I36, I37, I38, I39, I40, I41) f7(I42, I43, I44, I45, I46, I47) -> f8(I46, I47, rnd3, rnd4, rnd5, rnd6) [rnd6 = rnd4 /\ rnd5 = rnd3 /\ rnd4 = rnd4 /\ rnd3 = rnd3] f5(I48, I49, I50, I51, I52, I53) -> f6(I52, I53, I54, I51, I52, I55) [I55 = I54 /\ I54 = I54] f6(I56, I57, I58, I59, I60, I61) -> f4(I60, I61, I58, I59, I60, -1 + I60) f4(I62, I63, I64, I65, I66, I67) -> f3(I66, I67, I64, I65, I66, I67) [0 <= I67] f4(I68, I69, I70, I71, I72, I73) -> f1(I72, I73, I70, I71, I72, I73) [1 + I73 <= 0] f3(I74, I75, I76, I77, I78, I79) -> f5(I78, I79, I80, I77, I79, I81) [I81 = I80 /\ I80 = I80] f3(I82, I83, I84, I85, I86, I87) -> f4(I86, I87, I84, I85, I86, -1 + I87) f1(I88, I89, I90, I91, I92, I93) -> f2(I92, I93, I94, I95, I96, I97) [I97 = I95 /\ I96 = I94 /\ I95 = I95 /\ I94 = I94] We use the extended value criterion with the projection function NU: NU[f3#(x0,x1,x2,x3,x4,x5)] = x5 NU[f4#(x0,x1,x2,x3,x4,x5)] = x5 + 1 NU[f6#(x0,x1,x2,x3,x4,x5)] = x4 NU[f5#(x0,x1,x2,x3,x4,x5)] = x4
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