details

property	value
status	complete
benchmark	byron-2.t2.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n078.star.cs.uiowa.edu
space	From_T2

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	30.2040932178 seconds
cpu usage	31.853191604
max memory	3.088384E7

stage attributes

key	value
output-size	11561
starexec-result	YES

output

/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES DP problem for innermost termination. P = f8#(x1, x2, x3, x4, x5, x6, x7, x8) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8) f7#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) f6#(I8, I9, I10, I11, I12, I13, I14, I15) -> f7#(I8, rnd2, I10, I11, I12, I13, -1 + I14, rnd8) [y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2] f5#(I16, I17, I18, I19, I20, I21, I22, I23) -> f6#(I16, I17, I18, I19, I20, I21, I22, I23) [I16 = I16] f2#(I24, I25, I26, I27, I28, I29, I30, I31) -> f5#(I24, I32, I26, rnd4, I28, I29, I30, I31) [1 <= I30 /\ I33 = I33 /\ rnd4 = I33 /\ I32 = I32] f4#(I34, I35, I36, I37, I38, I39, I40, I41) -> f2#(I34, I35, I36, I37, I38, I39, I40, I41) f2#(I42, I43, I44, I45, I46, I47, I48, I49) -> f4#(I42, I50, I44, I51, I46, rnd6, I48, -1 + I49) [1 <= I48 /\ I52 = I52 /\ I51 = I52 /\ I50 = I50 /\ 0 <= I51 /\ I51 <= 0 /\ rnd6 = rnd6 /\ 2 <= -1 + I49] f1#(I61, I62, I63, I64, I65, I66, I67, I68) -> f2#(I61, I62, I63, I64, I65, I66, I67, I68) R = f8(x1, x2, x3, x4, x5, x6, x7, x8) -> f1(x1, x2, x3, x4, x5, x6, x7, x8) f7(I0, I1, I2, I3, I4, I5, I6, I7) -> f2(I0, I1, I2, I3, I4, I5, I6, I7) f6(I8, I9, I10, I11, I12, I13, I14, I15) -> f7(I8, rnd2, I10, I11, I12, I13, -1 + I14, rnd8) [y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2] f5(I16, I17, I18, I19, I20, I21, I22, I23) -> f6(I16, I17, I18, I19, I20, I21, I22, I23) [I16 = I16] f2(I24, I25, I26, I27, I28, I29, I30, I31) -> f5(I24, I32, I26, rnd4, I28, I29, I30, I31) [1 <= I30 /\ I33 = I33 /\ rnd4 = I33 /\ I32 = I32] f4(I34, I35, I36, I37, I38, I39, I40, I41) -> f2(I34, I35, I36, I37, I38, I39, I40, I41) f2(I42, I43, I44, I45, I46, I47, I48, I49) -> f4(I42, I50, I44, I51, I46, rnd6, I48, -1 + I49) [1 <= I48 /\ I52 = I52 /\ I51 = I52 /\ I50 = I50 /\ 0 <= I51 /\ I51 <= 0 /\ rnd6 = rnd6 /\ 2 <= -1 + I49] f2(I53, I54, I55, I56, I57, I58, I59, I60) -> f3(I53, I54, I57, I56, I57, I58, I59, I60) [I59 <= 0] f1(I61, I62, I63, I64, I65, I66, I67, I68) -> f2(I61, I62, I63, I64, I65, I66, I67, I68) The dependency graph for this problem is: 0 -> 7 1 -> 4, 6 2 -> 1 3 -> 2 4 -> 3 5 -> 4, 6 6 -> 5 7 -> 4, 6 Where: 0) f8#(x1, x2, x3, x4, x5, x6, x7, x8) -> f1#(x1, x2, x3, x4, x5, x6, x7, x8) 1) f7#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) 2) f6#(I8, I9, I10, I11, I12, I13, I14, I15) -> f7#(I8, rnd2, I10, I11, I12, I13, -1 + I14, rnd8) [y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2] 3) f5#(I16, I17, I18, I19, I20, I21, I22, I23) -> f6#(I16, I17, I18, I19, I20, I21, I22, I23) [I16 = I16] 4) f2#(I24, I25, I26, I27, I28, I29, I30, I31) -> f5#(I24, I32, I26, rnd4, I28, I29, I30, I31) [1 <= I30 /\ I33 = I33 /\ rnd4 = I33 /\ I32 = I32] 5) f4#(I34, I35, I36, I37, I38, I39, I40, I41) -> f2#(I34, I35, I36, I37, I38, I39, I40, I41) 6) f2#(I42, I43, I44, I45, I46, I47, I48, I49) -> f4#(I42, I50, I44, I51, I46, rnd6, I48, -1 + I49) [1 <= I48 /\ I52 = I52 /\ I51 = I52 /\ I50 = I50 /\ 0 <= I51 /\ I51 <= 0 /\ rnd6 = rnd6 /\ 2 <= -1 + I49] 7) f1#(I61, I62, I63, I64, I65, I66, I67, I68) -> f2#(I61, I62, I63, I64, I65, I66, I67, I68) We have the following SCCs. { 1, 2, 3, 4, 5, 6 } DP problem for innermost termination. P = f7#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) f6#(I8, I9, I10, I11, I12, I13, I14, I15) -> f7#(I8, rnd2, I10, I11, I12, I13, -1 + I14, rnd8) [y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2] f5#(I16, I17, I18, I19, I20, I21, I22, I23) -> f6#(I16, I17, I18, I19, I20, I21, I22, I23) [I16 = I16] f2#(I24, I25, I26, I27, I28, I29, I30, I31) -> f5#(I24, I32, I26, rnd4, I28, I29, I30, I31) [1 <= I30 /\ I33 = I33 /\ rnd4 = I33 /\ I32 = I32] f4#(I34, I35, I36, I37, I38, I39, I40, I41) -> f2#(I34, I35, I36, I37, I38, I39, I40, I41) f2#(I42, I43, I44, I45, I46, I47, I48, I49) -> f4#(I42, I50, I44, I51, I46, rnd6, I48, -1 + I49) [1 <= I48 /\ I52 = I52 /\ I51 = I52 /\ I50 = I50 /\ 0 <= I51 /\ I51 <= 0 /\ rnd6 = rnd6 /\ 2 <= -1 + I49] R = f8(x1, x2, x3, x4, x5, x6, x7, x8) -> f1(x1, x2, x3, x4, x5, x6, x7, x8) f7(I0, I1, I2, I3, I4, I5, I6, I7) -> f2(I0, I1, I2, I3, I4, I5, I6, I7) f6(I8, I9, I10, I11, I12, I13, I14, I15) -> f7(I8, rnd2, I10, I11, I12, I13, -1 + I14, rnd8) [y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2] f5(I16, I17, I18, I19, I20, I21, I22, I23) -> f6(I16, I17, I18, I19, I20, I21, I22, I23) [I16 = I16] f2(I24, I25, I26, I27, I28, I29, I30, I31) -> f5(I24, I32, I26, rnd4, I28, I29, I30, I31) [1 <= I30 /\ I33 = I33 /\ rnd4 = I33 /\ I32 = I32] f4(I34, I35, I36, I37, I38, I39, I40, I41) -> f2(I34, I35, I36, I37, I38, I39, I40, I41) f2(I42, I43, I44, I45, I46, I47, I48, I49) -> f4(I42, I50, I44, I51, I46, rnd6, I48, -1 + I49) [1 <= I48 /\ I52 = I52 /\ I51 = I52 /\ I50 = I50 /\ 0 <= I51 /\ I51 <= 0 /\ rnd6 = rnd6 /\ 2 <= -1 + I49] f2(I53, I54, I55, I56, I57, I58, I59, I60) -> f3(I53, I54, I57, I56, I57, I58, I59, I60) [I59 <= 0] f1(I61, I62, I63, I64, I65, I66, I67, I68) -> f2(I61, I62, I63, I64, I65, I66, I67, I68) We use the extended value criterion with the projection function NU: NU[f4#(x0,x1,x2,x3,x4,x5,x6,x7)] = x6 - 1 NU[f5#(x0,x1,x2,x3,x4,x5,x6,x7)] = x6 - 2 NU[f6#(x0,x1,x2,x3,x4,x5,x6,x7)] = x6 - 2 NU[f2#(x0,x1,x2,x3,x4,x5,x6,x7)] = x6 - 1 NU[f7#(x0,x1,x2,x3,x4,x5,x6,x7)] = x6 - 1 This gives the following inequalities: ==> I6 - 1 >= I6 - 1 y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2 ==> I14 - 2 >= (-1 + I14) - 1 I16 = I16 ==> I22 - 2 >= I22 - 2 1 <= I30 /\ I33 = I33 /\ rnd4 = I33 /\ I32 = I32 ==> I30 - 1 > I30 - 2 with I30 - 1 >= 0 ==> I40 - 1 >= I40 - 1 1 <= I48 /\ I52 = I52 /\ I51 = I52 /\ I50 = I50 /\ 0 <= I51 /\ I51 <= 0 /\ rnd6 = rnd6 /\ 2 <= -1 + I49 ==> I48 - 1 >= I48 - 1 We remove all the strictly oriented dependency pairs. DP problem for innermost termination. P = f7#(I0, I1, I2, I3, I4, I5, I6, I7) -> f2#(I0, I1, I2, I3, I4, I5, I6, I7) f6#(I8, I9, I10, I11, I12, I13, I14, I15) -> f7#(I8, rnd2, I10, I11, I12, I13, -1 + I14, rnd8) [y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2] f5#(I16, I17, I18, I19, I20, I21, I22, I23) -> f6#(I16, I17, I18, I19, I20, I21, I22, I23) [I16 = I16] f4#(I34, I35, I36, I37, I38, I39, I40, I41) -> f2#(I34, I35, I36, I37, I38, I39, I40, I41) f2#(I42, I43, I44, I45, I46, I47, I48, I49) -> f4#(I42, I50, I44, I51, I46, rnd6, I48, -1 + I49) [1 <= I48 /\ I52 = I52 /\ I51 = I52 /\ I50 = I50 /\ 0 <= I51 /\ I51 <= 0 /\ rnd6 = rnd6 /\ 2 <= -1 + I49] R = f8(x1, x2, x3, x4, x5, x6, x7, x8) -> f1(x1, x2, x3, x4, x5, x6, x7, x8) f7(I0, I1, I2, I3, I4, I5, I6, I7) -> f2(I0, I1, I2, I3, I4, I5, I6, I7) f6(I8, I9, I10, I11, I12, I13, I14, I15) -> f7(I8, rnd2, I10, I11, I12, I13, -1 + I14, rnd8) [y1 = y1 /\ rnd8 = y1 /\ rnd2 = rnd2] f5(I16, I17, I18, I19, I20, I21, I22, I23) -> f6(I16, I17, I18, I19, I20, I21, I22, I23) [I16 = I16] f2(I24, I25, I26, I27, I28, I29, I30, I31) -> f5(I24, I32, I26, rnd4, I28, I29, I30, I31) [1 <= I30 /\ I33 = I33 /\ rnd4 = I33 /\ I32 = I32] popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to Integ Trans Syste 27634