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Integ Trans Syste 27634 pair #381737539
details
property
value
status
complete
benchmark
small28.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n007.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
1.02058982849 seconds
cpu usage
1.076097664
max memory
1.3422592E7
stage attributes
key
value
output-size
1828
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES DP problem for innermost termination. P = f4#(x1, x2) -> f3#(x1, x2) f3#(I0, I1) -> f1#(I0, I1) f2#(I2, I3) -> f1#(I2, I3) f1#(I4, I5) -> f2#(1 + I4, I5) [I5 <= I4 /\ I4 <= I5] R = f4(x1, x2) -> f3(x1, x2) f3(I0, I1) -> f1(I0, I1) f2(I2, I3) -> f1(I2, I3) f1(I4, I5) -> f2(1 + I4, I5) [I5 <= I4 /\ I4 <= I5] The dependency graph for this problem is: 0 -> 1 1 -> 3 2 -> 3 3 -> 2 Where: 0) f4#(x1, x2) -> f3#(x1, x2) 1) f3#(I0, I1) -> f1#(I0, I1) 2) f2#(I2, I3) -> f1#(I2, I3) 3) f1#(I4, I5) -> f2#(1 + I4, I5) [I5 <= I4 /\ I4 <= I5] We have the following SCCs. { 2, 3 } DP problem for innermost termination. P = f2#(I2, I3) -> f1#(I2, I3) f1#(I4, I5) -> f2#(1 + I4, I5) [I5 <= I4 /\ I4 <= I5] R = f4(x1, x2) -> f3(x1, x2) f3(I0, I1) -> f1(I0, I1) f2(I2, I3) -> f1(I2, I3) f1(I4, I5) -> f2(1 + I4, I5) [I5 <= I4 /\ I4 <= I5] We use the reverse value criterion with the projection function NU: NU[f1#(z1,z2)] = z2 + -1 * z1 NU[f2#(z1,z2)] = z2 + -1 * z1 This gives the following inequalities: ==> I3 + -1 * I2 >= I3 + -1 * I2 I5 <= I4 /\ I4 <= I5 ==> I5 + -1 * I4 > I5 + -1 * (1 + I4) with I5 + -1 * I4 >= 0 We remove all the strictly oriented dependency pairs. DP problem for innermost termination. P = f2#(I2, I3) -> f1#(I2, I3) R = f4(x1, x2) -> f3(x1, x2) f3(I0, I1) -> f1(I0, I1) f2(I2, I3) -> f1(I2, I3) f1(I4, I5) -> f2(1 + I4, I5) [I5 <= I4 /\ I4 <= I5] The dependency graph for this problem is: 2 -> Where: 2) f2#(I2, I3) -> f1#(I2, I3) We have the following SCCs.
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