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Integ Trans Syste 27634 pair #381737959
details
property
value
status
complete
benchmark
consts4.t2_fixed.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n080.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
0.105817079544 seconds
cpu usage
0.105585841
max memory
8622080.0
stage attributes
key
value
output-size
1560
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES DP problem for innermost termination. P = f4#(x1) -> f3#(x1) f3#(I0) -> f1#(I0) f2#(I1) -> f1#(I1) f1#(I2) -> f2#(-1000 + I2) [201 <= -1000 + I2] R = f4(x1) -> f3(x1) f3(I0) -> f1(I0) f2(I1) -> f1(I1) f1(I2) -> f2(-1000 + I2) [201 <= -1000 + I2] The dependency graph for this problem is: 0 -> 1 1 -> 3 2 -> 3 3 -> 2 Where: 0) f4#(x1) -> f3#(x1) 1) f3#(I0) -> f1#(I0) 2) f2#(I1) -> f1#(I1) 3) f1#(I2) -> f2#(-1000 + I2) [201 <= -1000 + I2] We have the following SCCs. { 2, 3 } DP problem for innermost termination. P = f2#(I1) -> f1#(I1) f1#(I2) -> f2#(-1000 + I2) [201 <= -1000 + I2] R = f4(x1) -> f3(x1) f3(I0) -> f1(I0) f2(I1) -> f1(I1) f1(I2) -> f2(-1000 + I2) [201 <= -1000 + I2] We use the basic value criterion with the projection function NU: NU[f1#(z1)] = z1 NU[f2#(z1)] = z1 This gives the following inequalities: ==> I1 (>! \union =) I1 201 <= -1000 + I2 ==> I2 >! -1000 + I2 We remove all the strictly oriented dependency pairs. DP problem for innermost termination. P = f2#(I1) -> f1#(I1) R = f4(x1) -> f3(x1) f3(I0) -> f1(I0) f2(I1) -> f1(I1) f1(I2) -> f2(-1000 + I2) [201 <= -1000 + I2] The dependency graph for this problem is: 2 -> Where: 2) f2#(I1) -> f1#(I1) We have the following SCCs.
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