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Integ Trans Syste 27634 pair #381738068
details
property
value
status
complete
benchmark
MinusUserDefined.jar-obl-8.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n002.star.cs.uiowa.edu
space
From_AProVE_2014
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
0.686045885086 seconds
cpu usage
0.717449507
max memory
1.1804672E7
stage attributes
key
value
output-size
2418
starexec-result
MAYBE
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = init#(x1, x2, x3, x4, x5) -> f1#(rnd1, rnd2, rnd3, rnd4, rnd5) f2#(I0, I1, I2, I3, I4) -> f2#(I0, I1 + 1, I0, I1 + 1, I0) [I2 = I4 /\ 0 = I3 /\ 0 <= I2 - 1] f2#(I5, I6, I7, I8, I9) -> f2#(I5, I6, I7 - 1, I8 - 1, I7 - 1) [I7 = I9 /\ 0 <= I8 - 1 /\ 0 <= I7 - 1] f1#(I10, I11, I12, I13, I14) -> f2#(I15, I16, I17, I18, I19) [I15 = I19 /\ I16 = I18 /\ I15 = I17 /\ 0 <= I10 - 1 /\ -1 <= I15 - 1 /\ -1 <= I11 - 1 /\ -1 <= I16 - 1] R = init(x1, x2, x3, x4, x5) -> f1(rnd1, rnd2, rnd3, rnd4, rnd5) f2(I0, I1, I2, I3, I4) -> f2(I0, I1 + 1, I0, I1 + 1, I0) [I2 = I4 /\ 0 = I3 /\ 0 <= I2 - 1] f2(I5, I6, I7, I8, I9) -> f2(I5, I6, I7 - 1, I8 - 1, I7 - 1) [I7 = I9 /\ 0 <= I8 - 1 /\ 0 <= I7 - 1] f1(I10, I11, I12, I13, I14) -> f2(I15, I16, I17, I18, I19) [I15 = I19 /\ I16 = I18 /\ I15 = I17 /\ 0 <= I10 - 1 /\ -1 <= I15 - 1 /\ -1 <= I11 - 1 /\ -1 <= I16 - 1] The dependency graph for this problem is: 0 -> 3 1 -> 1, 2 2 -> 1, 2 3 -> 1, 2 Where: 0) init#(x1, x2, x3, x4, x5) -> f1#(rnd1, rnd2, rnd3, rnd4, rnd5) 1) f2#(I0, I1, I2, I3, I4) -> f2#(I0, I1 + 1, I0, I1 + 1, I0) [I2 = I4 /\ 0 = I3 /\ 0 <= I2 - 1] 2) f2#(I5, I6, I7, I8, I9) -> f2#(I5, I6, I7 - 1, I8 - 1, I7 - 1) [I7 = I9 /\ 0 <= I8 - 1 /\ 0 <= I7 - 1] 3) f1#(I10, I11, I12, I13, I14) -> f2#(I15, I16, I17, I18, I19) [I15 = I19 /\ I16 = I18 /\ I15 = I17 /\ 0 <= I10 - 1 /\ -1 <= I15 - 1 /\ -1 <= I11 - 1 /\ -1 <= I16 - 1] We have the following SCCs. { 1, 2 } DP problem for innermost termination. P = f2#(I0, I1, I2, I3, I4) -> f2#(I0, I1 + 1, I0, I1 + 1, I0) [I2 = I4 /\ 0 = I3 /\ 0 <= I2 - 1] f2#(I5, I6, I7, I8, I9) -> f2#(I5, I6, I7 - 1, I8 - 1, I7 - 1) [I7 = I9 /\ 0 <= I8 - 1 /\ 0 <= I7 - 1] R = init(x1, x2, x3, x4, x5) -> f1(rnd1, rnd2, rnd3, rnd4, rnd5) f2(I0, I1, I2, I3, I4) -> f2(I0, I1 + 1, I0, I1 + 1, I0) [I2 = I4 /\ 0 = I3 /\ 0 <= I2 - 1] f2(I5, I6, I7, I8, I9) -> f2(I5, I6, I7 - 1, I8 - 1, I7 - 1) [I7 = I9 /\ 0 <= I8 - 1 /\ 0 <= I7 - 1] f1(I10, I11, I12, I13, I14) -> f2(I15, I16, I17, I18, I19) [I15 = I19 /\ I16 = I18 /\ I15 = I17 /\ 0 <= I10 - 1 /\ -1 <= I15 - 1 /\ -1 <= I11 - 1 /\ -1 <= I16 - 1]
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