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Integ Trans Syste 27634 pair #381738337
details
property
value
status
complete
benchmark
florian_pldi.t2.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n052.star.cs.uiowa.edu
space
From_T2
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
20.3906121254 seconds
cpu usage
21.722216663
max memory
2.8045312E7
stage attributes
key
value
output-size
11227
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES DP problem for innermost termination. P = f10#(x1, x2, x3, x4) -> f9#(x1, x2, x3, x4) f9#(I0, I1, I2, I3) -> f2#(I0, 0, I2, I3) f3#(I4, I5, I6, I7) -> f8#(I4, I5, I6, I7) [1 + I4 <= 0] f3#(I8, I9, I10, I11) -> f8#(I8, I9, I10, I11) [1 <= I8] f3#(I12, I13, I14, I15) -> f7#(I12, I13, I14, I15) [0 <= I12 /\ I12 <= 0] f8#(I16, I17, I18, I19) -> f7#(I16, I17, -1 + I18, -1 + I19) f7#(I20, I21, I22, I23) -> f6#(I20, I21, 1 + I22, I23) f6#(I24, I25, I26, I27) -> f1#(I24, I25, I26, I27) f2#(I28, I29, I30, I31) -> f4#(I28, I29, I30, I31) f4#(I32, I33, I34, I35) -> f6#(I32, I33, 1 + I33, I35) [1 + I33 <= I35] f1#(I40, I41, I42, I43) -> f3#(rnd1, I41, I42, I43) [rnd1 = rnd1 /\ 1 + I42 <= I43] f1#(I44, I45, I46, I47) -> f2#(I44, 1 + I45, I46, I47) [I47 <= I46] R = f10(x1, x2, x3, x4) -> f9(x1, x2, x3, x4) f9(I0, I1, I2, I3) -> f2(I0, 0, I2, I3) f3(I4, I5, I6, I7) -> f8(I4, I5, I6, I7) [1 + I4 <= 0] f3(I8, I9, I10, I11) -> f8(I8, I9, I10, I11) [1 <= I8] f3(I12, I13, I14, I15) -> f7(I12, I13, I14, I15) [0 <= I12 /\ I12 <= 0] f8(I16, I17, I18, I19) -> f7(I16, I17, -1 + I18, -1 + I19) f7(I20, I21, I22, I23) -> f6(I20, I21, 1 + I22, I23) f6(I24, I25, I26, I27) -> f1(I24, I25, I26, I27) f2(I28, I29, I30, I31) -> f4(I28, I29, I30, I31) f4(I32, I33, I34, I35) -> f6(I32, I33, 1 + I33, I35) [1 + I33 <= I35] f4(I36, I37, I38, I39) -> f5(I36, I37, I38, I39) [I39 <= I37] f1(I40, I41, I42, I43) -> f3(rnd1, I41, I42, I43) [rnd1 = rnd1 /\ 1 + I42 <= I43] f1(I44, I45, I46, I47) -> f2(I44, 1 + I45, I46, I47) [I47 <= I46] The dependency graph for this problem is: 0 -> 1 1 -> 8 2 -> 5 3 -> 5 4 -> 6 5 -> 6 6 -> 7 7 -> 10, 11 8 -> 9 9 -> 7 10 -> 2, 3, 4 11 -> 8 Where: 0) f10#(x1, x2, x3, x4) -> f9#(x1, x2, x3, x4) 1) f9#(I0, I1, I2, I3) -> f2#(I0, 0, I2, I3) 2) f3#(I4, I5, I6, I7) -> f8#(I4, I5, I6, I7) [1 + I4 <= 0] 3) f3#(I8, I9, I10, I11) -> f8#(I8, I9, I10, I11) [1 <= I8] 4) f3#(I12, I13, I14, I15) -> f7#(I12, I13, I14, I15) [0 <= I12 /\ I12 <= 0] 5) f8#(I16, I17, I18, I19) -> f7#(I16, I17, -1 + I18, -1 + I19) 6) f7#(I20, I21, I22, I23) -> f6#(I20, I21, 1 + I22, I23) 7) f6#(I24, I25, I26, I27) -> f1#(I24, I25, I26, I27) 8) f2#(I28, I29, I30, I31) -> f4#(I28, I29, I30, I31) 9) f4#(I32, I33, I34, I35) -> f6#(I32, I33, 1 + I33, I35) [1 + I33 <= I35] 10) f1#(I40, I41, I42, I43) -> f3#(rnd1, I41, I42, I43) [rnd1 = rnd1 /\ 1 + I42 <= I43] 11) f1#(I44, I45, I46, I47) -> f2#(I44, 1 + I45, I46, I47) [I47 <= I46] We have the following SCCs. { 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 } DP problem for innermost termination. P = f3#(I4, I5, I6, I7) -> f8#(I4, I5, I6, I7) [1 + I4 <= 0] f3#(I8, I9, I10, I11) -> f8#(I8, I9, I10, I11) [1 <= I8] f3#(I12, I13, I14, I15) -> f7#(I12, I13, I14, I15) [0 <= I12 /\ I12 <= 0] f8#(I16, I17, I18, I19) -> f7#(I16, I17, -1 + I18, -1 + I19) f7#(I20, I21, I22, I23) -> f6#(I20, I21, 1 + I22, I23) f6#(I24, I25, I26, I27) -> f1#(I24, I25, I26, I27) f2#(I28, I29, I30, I31) -> f4#(I28, I29, I30, I31) f4#(I32, I33, I34, I35) -> f6#(I32, I33, 1 + I33, I35) [1 + I33 <= I35] f1#(I40, I41, I42, I43) -> f3#(rnd1, I41, I42, I43) [rnd1 = rnd1 /\ 1 + I42 <= I43] f1#(I44, I45, I46, I47) -> f2#(I44, 1 + I45, I46, I47) [I47 <= I46] R = f10(x1, x2, x3, x4) -> f9(x1, x2, x3, x4) f9(I0, I1, I2, I3) -> f2(I0, 0, I2, I3) f3(I4, I5, I6, I7) -> f8(I4, I5, I6, I7) [1 + I4 <= 0] f3(I8, I9, I10, I11) -> f8(I8, I9, I10, I11) [1 <= I8] f3(I12, I13, I14, I15) -> f7(I12, I13, I14, I15) [0 <= I12 /\ I12 <= 0] f8(I16, I17, I18, I19) -> f7(I16, I17, -1 + I18, -1 + I19) f7(I20, I21, I22, I23) -> f6(I20, I21, 1 + I22, I23) f6(I24, I25, I26, I27) -> f1(I24, I25, I26, I27) f2(I28, I29, I30, I31) -> f4(I28, I29, I30, I31) f4(I32, I33, I34, I35) -> f6(I32, I33, 1 + I33, I35) [1 + I33 <= I35] f4(I36, I37, I38, I39) -> f5(I36, I37, I38, I39) [I39 <= I37] f1(I40, I41, I42, I43) -> f3(rnd1, I41, I42, I43) [rnd1 = rnd1 /\ 1 + I42 <= I43] f1(I44, I45, I46, I47) -> f2(I44, 1 + I45, I46, I47) [I47 <= I46] We use the extended value criterion with the projection function NU: NU[f4#(x0,x1,x2,x3)] = -x1 + x3 + 1 NU[f2#(x0,x1,x2,x3)] = -x1 + x3 + 1 NU[f1#(x0,x1,x2,x3)] = -x1 + x3 NU[f6#(x0,x1,x2,x3)] = -x1 + x3 NU[f7#(x0,x1,x2,x3)] = -x1 + x3
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