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Integ Trans Syste 27634 pair #381738446
details
property
value
status
complete
benchmark
LogAG.jar-obl-8.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n036.star.cs.uiowa.edu
space
From_AProVE_2014
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
1.74671387672 seconds
cpu usage
1.85331148
max memory
1.7821696E7
stage attributes
key
value
output-size
1713
starexec-result
MAYBE
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = init#(x1, x2) -> f1#(rnd1, rnd2) f3#(I0, I1) -> f2#(I0 + 1, I2) [I1 <= 1 /\ -1 <= I0 - 1] f3#(I3, I4) -> f3#(I3 + 1, I4 - 2) [1 <= I4 - 1] f2#(I5, I6) -> f3#(0, I5 - 2) [1 <= I5 - 1] f1#(I7, I8) -> f2#(I9, I10) [0 <= I7 - 1 /\ -1 <= I9 - 1 /\ -1 <= I8 - 1] R = init(x1, x2) -> f1(rnd1, rnd2) f3(I0, I1) -> f2(I0 + 1, I2) [I1 <= 1 /\ -1 <= I0 - 1] f3(I3, I4) -> f3(I3 + 1, I4 - 2) [1 <= I4 - 1] f2(I5, I6) -> f3(0, I5 - 2) [1 <= I5 - 1] f1(I7, I8) -> f2(I9, I10) [0 <= I7 - 1 /\ -1 <= I9 - 1 /\ -1 <= I8 - 1] The dependency graph for this problem is: 0 -> 4 1 -> 3 2 -> 1, 2 3 -> 1, 2 4 -> 3 Where: 0) init#(x1, x2) -> f1#(rnd1, rnd2) 1) f3#(I0, I1) -> f2#(I0 + 1, I2) [I1 <= 1 /\ -1 <= I0 - 1] 2) f3#(I3, I4) -> f3#(I3 + 1, I4 - 2) [1 <= I4 - 1] 3) f2#(I5, I6) -> f3#(0, I5 - 2) [1 <= I5 - 1] 4) f1#(I7, I8) -> f2#(I9, I10) [0 <= I7 - 1 /\ -1 <= I9 - 1 /\ -1 <= I8 - 1] We have the following SCCs. { 1, 2, 3 } DP problem for innermost termination. P = f3#(I0, I1) -> f2#(I0 + 1, I2) [I1 <= 1 /\ -1 <= I0 - 1] f3#(I3, I4) -> f3#(I3 + 1, I4 - 2) [1 <= I4 - 1] f2#(I5, I6) -> f3#(0, I5 - 2) [1 <= I5 - 1] R = init(x1, x2) -> f1(rnd1, rnd2) f3(I0, I1) -> f2(I0 + 1, I2) [I1 <= 1 /\ -1 <= I0 - 1] f3(I3, I4) -> f3(I3 + 1, I4 - 2) [1 <= I4 - 1] f2(I5, I6) -> f3(0, I5 - 2) [1 <= I5 - 1] f1(I7, I8) -> f2(I9, I10) [0 <= I7 - 1 /\ -1 <= I9 - 1 /\ -1 <= I8 - 1]
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