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Integ Trans Syste 27634 pair #381738488
details
property
value
status
complete
benchmark
Velroyen08-ex01.jar-obl-8.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n035.star.cs.uiowa.edu
space
From_AProVE_2014
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
0.660403966904 seconds
cpu usage
0.37732837
max memory
1.0063872E7
stage attributes
key
value
output-size
1936
starexec-result
MAYBE
output
/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = init#(x1, x2) -> f1#(rnd1, rnd2) f3#(I0, I1) -> f3#(I0 - 1, I2) [I0 <= -1] f2#(I3, I4) -> f3#(I5, I6) [-1 <= y1 - 1 /\ 1 <= I4 - 1 /\ y2 - 2 * y3 = 0 /\ -1 <= y2 - 1 /\ 0 <= I3 - 1 /\ y2 - 2 * y3 <= 1 /\ 0 <= y2 - 2 * y3 /\ 0 - y1 = I5] f1#(I7, I8) -> f2#(I7, I8) [-1 <= I9 - 1 /\ 1 <= I8 - 1 /\ I10 - 2 * I11 = 0 /\ -1 <= I10 - 1 /\ 0 <= I7 - 1] R = init(x1, x2) -> f1(rnd1, rnd2) f3(I0, I1) -> f3(I0 - 1, I2) [I0 <= -1] f2(I3, I4) -> f3(I5, I6) [-1 <= y1 - 1 /\ 1 <= I4 - 1 /\ y2 - 2 * y3 = 0 /\ -1 <= y2 - 1 /\ 0 <= I3 - 1 /\ y2 - 2 * y3 <= 1 /\ 0 <= y2 - 2 * y3 /\ 0 - y1 = I5] f1(I7, I8) -> f2(I7, I8) [-1 <= I9 - 1 /\ 1 <= I8 - 1 /\ I10 - 2 * I11 = 0 /\ -1 <= I10 - 1 /\ 0 <= I7 - 1] The dependency graph for this problem is: 0 -> 3 1 -> 1 2 -> 1 3 -> 2 Where: 0) init#(x1, x2) -> f1#(rnd1, rnd2) 1) f3#(I0, I1) -> f3#(I0 - 1, I2) [I0 <= -1] 2) f2#(I3, I4) -> f3#(I5, I6) [-1 <= y1 - 1 /\ 1 <= I4 - 1 /\ y2 - 2 * y3 = 0 /\ -1 <= y2 - 1 /\ 0 <= I3 - 1 /\ y2 - 2 * y3 <= 1 /\ 0 <= y2 - 2 * y3 /\ 0 - y1 = I5] 3) f1#(I7, I8) -> f2#(I7, I8) [-1 <= I9 - 1 /\ 1 <= I8 - 1 /\ I10 - 2 * I11 = 0 /\ -1 <= I10 - 1 /\ 0 <= I7 - 1] We have the following SCCs. { 1 } DP problem for innermost termination. P = f3#(I0, I1) -> f3#(I0 - 1, I2) [I0 <= -1] R = init(x1, x2) -> f1(rnd1, rnd2) f3(I0, I1) -> f3(I0 - 1, I2) [I0 <= -1] f2(I3, I4) -> f3(I5, I6) [-1 <= y1 - 1 /\ 1 <= I4 - 1 /\ y2 - 2 * y3 = 0 /\ -1 <= y2 - 1 /\ 0 <= I3 - 1 /\ y2 - 2 * y3 <= 1 /\ 0 <= y2 - 2 * y3 /\ 0 - y1 = I5] f1(I7, I8) -> f2(I7, I8) [-1 <= I9 - 1 /\ 1 <= I8 - 1 /\ I10 - 2 * I11 = 0 /\ -1 <= I10 - 1 /\ 0 <= I7 - 1]
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