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Integ Trans Syste 27634 pair #381738746
details
property
value
status
complete
benchmark
Velroyen08-whileNested.jar-obl-8.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n030.star.cs.uiowa.edu
space
From_AProVE_2014
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
0.395171880722 seconds
cpu usage
0.414223308
max memory
1.0510336E7
stage attributes
key
value
output-size
1753
starexec-result
MAYBE
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = init#(x1, x2, x3) -> f1#(rnd1, rnd2, rnd3) f3#(I0, I1, I2) -> f3#(I0, I1 + 1, I1 + 1) [I1 = I2 /\ 0 <= I1 - 1] f3#(I3, I4, I5) -> f2#(I3 + 1, I6, I7) [0 = I5 /\ 0 = I4] f2#(I8, I9, I10) -> f3#(I8, I8, I8) [I8 <= 9] f1#(I11, I12, I13) -> f2#(I12, I14, I15) [-1 <= I12 - 1 /\ 0 <= I11 - 1] R = init(x1, x2, x3) -> f1(rnd1, rnd2, rnd3) f3(I0, I1, I2) -> f3(I0, I1 + 1, I1 + 1) [I1 = I2 /\ 0 <= I1 - 1] f3(I3, I4, I5) -> f2(I3 + 1, I6, I7) [0 = I5 /\ 0 = I4] f2(I8, I9, I10) -> f3(I8, I8, I8) [I8 <= 9] f1(I11, I12, I13) -> f2(I12, I14, I15) [-1 <= I12 - 1 /\ 0 <= I11 - 1] The dependency graph for this problem is: 0 -> 4 1 -> 1 2 -> 3 3 -> 1, 2 4 -> 3 Where: 0) init#(x1, x2, x3) -> f1#(rnd1, rnd2, rnd3) 1) f3#(I0, I1, I2) -> f3#(I0, I1 + 1, I1 + 1) [I1 = I2 /\ 0 <= I1 - 1] 2) f3#(I3, I4, I5) -> f2#(I3 + 1, I6, I7) [0 = I5 /\ 0 = I4] 3) f2#(I8, I9, I10) -> f3#(I8, I8, I8) [I8 <= 9] 4) f1#(I11, I12, I13) -> f2#(I12, I14, I15) [-1 <= I12 - 1 /\ 0 <= I11 - 1] We have the following SCCs. { 2, 3 } { 1 } DP problem for innermost termination. P = f3#(I0, I1, I2) -> f3#(I0, I1 + 1, I1 + 1) [I1 = I2 /\ 0 <= I1 - 1] R = init(x1, x2, x3) -> f1(rnd1, rnd2, rnd3) f3(I0, I1, I2) -> f3(I0, I1 + 1, I1 + 1) [I1 = I2 /\ 0 <= I1 - 1] f3(I3, I4, I5) -> f2(I3 + 1, I6, I7) [0 = I5 /\ 0 = I4] f2(I8, I9, I10) -> f3(I8, I8, I8) [I8 <= 9] f1(I11, I12, I13) -> f2(I12, I14, I15) [-1 <= I12 - 1 /\ 0 <= I11 - 1]
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