details

property	value
status	complete
benchmark	Shuffle.jar-obl-10.smt2
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n105.star.cs.uiowa.edu
space	From_AProVE_2014

run statistics

property	value
solver	Ctrl
configuration	Transition
runtime (wallclock)	0.973770856857 seconds
cpu usage	1.01929412
max memory	1.2812288E7

stage attributes

key	value
output-size	5979
starexec-result	MAYBE

output

/export/starexec/sandbox2/solver/bin/starexec_run_Transition /export/starexec/sandbox2/benchmark/theBenchmark.smt2 /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = init#(x1, x2) -> f3#(rnd1, rnd2) f5#(I0, I1) -> f5#(I2, I3) [-1 <= I2 - 1 /\ 0 <= I0 - 1 /\ I2 + 1 <= I0] f2#(I4, I5) -> f5#(I6, I7) [0 <= y1 - 1 /\ 0 <= y2 - 1 /\ I6 + 2 <= I5 /\ 0 <= I4 - 1 /\ 2 <= I5 - 1 /\ 0 <= I6 - 1] f4#(I8, I9) -> f4#(I8 - 1, I9 + 1) [0 <= I9 - 1 /\ 0 <= I8 - 1] f3#(I10, I11) -> f4#(I12, 1) [0 <= I10 - 1 /\ -1 <= I12 - 1 /\ -1 <= I11 - 1] f2#(I13, I14) -> f2#(I15, I16) [0 <= I17 - 1 /\ 0 <= I18 - 1 /\ I15 <= I13 /\ I15 + 2 <= I14 /\ 0 <= I13 - 1 /\ 2 <= I14 - 1 /\ 0 <= I15 - 1 /\ -1 <= I16 - 1] f2#(I19, I20) -> f2#(I21, I22) [-1 <= I22 - 1 /\ 0 <= I21 - 1 /\ 1 <= I20 - 1 /\ 0 <= I19 - 1 /\ I22 + 2 <= I20 /\ I22 + 1 <= I19 /\ I21 + 1 <= I20 /\ I21 <= I19] f3#(I23, I24) -> f2#(I25, I26) [-1 <= I26 - 1 /\ 0 <= I25 - 1 /\ 0 <= I23 - 1 /\ I25 <= I23] f1#(I27, I28) -> f2#(I29, I30) [-1 <= I30 - 1 /\ 0 <= I29 - 1 /\ -1 <= I28 - 1 /\ 0 <= I27 - 1 /\ I30 <= I28 /\ I29 - 1 <= I28 /\ I29 <= I27] R = init(x1, x2) -> f3(rnd1, rnd2) f5(I0, I1) -> f5(I2, I3) [-1 <= I2 - 1 /\ 0 <= I0 - 1 /\ I2 + 1 <= I0] f2(I4, I5) -> f5(I6, I7) [0 <= y1 - 1 /\ 0 <= y2 - 1 /\ I6 + 2 <= I5 /\ 0 <= I4 - 1 /\ 2 <= I5 - 1 /\ 0 <= I6 - 1] f4(I8, I9) -> f4(I8 - 1, I9 + 1) [0 <= I9 - 1 /\ 0 <= I8 - 1] f3(I10, I11) -> f4(I12, 1) [0 <= I10 - 1 /\ -1 <= I12 - 1 /\ -1 <= I11 - 1] f2(I13, I14) -> f2(I15, I16) [0 <= I17 - 1 /\ 0 <= I18 - 1 /\ I15 <= I13 /\ I15 + 2 <= I14 /\ 0 <= I13 - 1 /\ 2 <= I14 - 1 /\ 0 <= I15 - 1 /\ -1 <= I16 - 1] f2(I19, I20) -> f2(I21, I22) [-1 <= I22 - 1 /\ 0 <= I21 - 1 /\ 1 <= I20 - 1 /\ 0 <= I19 - 1 /\ I22 + 2 <= I20 /\ I22 + 1 <= I19 /\ I21 + 1 <= I20 /\ I21 <= I19] f3(I23, I24) -> f2(I25, I26) [-1 <= I26 - 1 /\ 0 <= I25 - 1 /\ 0 <= I23 - 1 /\ I25 <= I23] f1(I27, I28) -> f2(I29, I30) [-1 <= I30 - 1 /\ 0 <= I29 - 1 /\ -1 <= I28 - 1 /\ 0 <= I27 - 1 /\ I30 <= I28 /\ I29 - 1 <= I28 /\ I29 <= I27] The dependency graph for this problem is: 0 -> 4, 7 1 -> 1 2 -> 1 3 -> 3 4 -> 3 5 -> 2, 5, 6 6 -> 2, 5, 6 7 -> 2, 5, 6 8 -> 2, 5, 6 Where: 0) init#(x1, x2) -> f3#(rnd1, rnd2) 1) f5#(I0, I1) -> f5#(I2, I3) [-1 <= I2 - 1 /\ 0 <= I0 - 1 /\ I2 + 1 <= I0] 2) f2#(I4, I5) -> f5#(I6, I7) [0 <= y1 - 1 /\ 0 <= y2 - 1 /\ I6 + 2 <= I5 /\ 0 <= I4 - 1 /\ 2 <= I5 - 1 /\ 0 <= I6 - 1] 3) f4#(I8, I9) -> f4#(I8 - 1, I9 + 1) [0 <= I9 - 1 /\ 0 <= I8 - 1] 4) f3#(I10, I11) -> f4#(I12, 1) [0 <= I10 - 1 /\ -1 <= I12 - 1 /\ -1 <= I11 - 1] 5) f2#(I13, I14) -> f2#(I15, I16) [0 <= I17 - 1 /\ 0 <= I18 - 1 /\ I15 <= I13 /\ I15 + 2 <= I14 /\ 0 <= I13 - 1 /\ 2 <= I14 - 1 /\ 0 <= I15 - 1 /\ -1 <= I16 - 1] 6) f2#(I19, I20) -> f2#(I21, I22) [-1 <= I22 - 1 /\ 0 <= I21 - 1 /\ 1 <= I20 - 1 /\ 0 <= I19 - 1 /\ I22 + 2 <= I20 /\ I22 + 1 <= I19 /\ I21 + 1 <= I20 /\ I21 <= I19] 7) f3#(I23, I24) -> f2#(I25, I26) [-1 <= I26 - 1 /\ 0 <= I25 - 1 /\ 0 <= I23 - 1 /\ I25 <= I23] 8) f1#(I27, I28) -> f2#(I29, I30) [-1 <= I30 - 1 /\ 0 <= I29 - 1 /\ -1 <= I28 - 1 /\ 0 <= I27 - 1 /\ I30 <= I28 /\ I29 - 1 <= I28 /\ I29 <= I27] We have the following SCCs. { 3 } { 5, 6 } { 1 } DP problem for innermost termination. P = f5#(I0, I1) -> f5#(I2, I3) [-1 <= I2 - 1 /\ 0 <= I0 - 1 /\ I2 + 1 <= I0] R = init(x1, x2) -> f3(rnd1, rnd2) f5(I0, I1) -> f5(I2, I3) [-1 <= I2 - 1 /\ 0 <= I0 - 1 /\ I2 + 1 <= I0] f2(I4, I5) -> f5(I6, I7) [0 <= y1 - 1 /\ 0 <= y2 - 1 /\ I6 + 2 <= I5 /\ 0 <= I4 - 1 /\ 2 <= I5 - 1 /\ 0 <= I6 - 1] f4(I8, I9) -> f4(I8 - 1, I9 + 1) [0 <= I9 - 1 /\ 0 <= I8 - 1] f3(I10, I11) -> f4(I12, 1) [0 <= I10 - 1 /\ -1 <= I12 - 1 /\ -1 <= I11 - 1] f2(I13, I14) -> f2(I15, I16) [0 <= I17 - 1 /\ 0 <= I18 - 1 /\ I15 <= I13 /\ I15 + 2 <= I14 /\ 0 <= I13 - 1 /\ 2 <= I14 - 1 /\ 0 <= I15 - 1 /\ -1 <= I16 - 1] f2(I19, I20) -> f2(I21, I22) [-1 <= I22 - 1 /\ 0 <= I21 - 1 /\ 1 <= I20 - 1 /\ 0 <= I19 - 1 /\ I22 + 2 <= I20 /\ I22 + 1 <= I19 /\ I21 + 1 <= I20 /\ I21 <= I19] f3(I23, I24) -> f2(I25, I26) [-1 <= I26 - 1 /\ 0 <= I25 - 1 /\ 0 <= I23 - 1 /\ I25 <= I23] f1(I27, I28) -> f2(I29, I30) [-1 <= I30 - 1 /\ 0 <= I29 - 1 /\ -1 <= I28 - 1 /\ 0 <= I27 - 1 /\ I30 <= I28 /\ I29 - 1 <= I28 /\ I29 <= I27] We use the basic value criterion with the projection function NU: NU[f5#(z1,z2)] = z1 This gives the following inequalities: -1 <= I2 - 1 /\ 0 <= I0 - 1 /\ I2 + 1 <= I0 ==> I0 >! I2 All dependency pairs are strictly oriented, so the entire dependency pair problem may be removed. DP problem for innermost termination. P = f2#(I13, I14) -> f2#(I15, I16) [0 <= I17 - 1 /\ 0 <= I18 - 1 /\ I15 <= I13 /\ I15 + 2 <= I14 /\ 0 <= I13 - 1 /\ 2 <= I14 - 1 /\ 0 <= I15 - 1 /\ -1 <= I16 - 1] f2#(I19, I20) -> f2#(I21, I22) [-1 <= I22 - 1 /\ 0 <= I21 - 1 /\ 1 <= I20 - 1 /\ 0 <= I19 - 1 /\ I22 + 2 <= I20 /\ I22 + 1 <= I19 /\ I21 + 1 <= I20 /\ I21 <= I19] R = init(x1, x2) -> f3(rnd1, rnd2) f5(I0, I1) -> f5(I2, I3) [-1 <= I2 - 1 /\ 0 <= I0 - 1 /\ I2 + 1 <= I0] f2(I4, I5) -> f5(I6, I7) [0 <= y1 - 1 /\ 0 <= y2 - 1 /\ I6 + 2 <= I5 /\ 0 <= I4 - 1 /\ 2 <= I5 - 1 /\ 0 <= I6 - 1] f4(I8, I9) -> f4(I8 - 1, I9 + 1) [0 <= I9 - 1 /\ 0 <= I8 - 1] f3(I10, I11) -> f4(I12, 1) [0 <= I10 - 1 /\ -1 <= I12 - 1 /\ -1 <= I11 - 1] f2(I13, I14) -> f2(I15, I16) [0 <= I17 - 1 /\ 0 <= I18 - 1 /\ I15 <= I13 /\ I15 + 2 <= I14 /\ 0 <= I13 - 1 /\ 2 <= I14 - 1 /\ 0 <= I15 - 1 /\ -1 <= I16 - 1] f2(I19, I20) -> f2(I21, I22) [-1 <= I22 - 1 /\ 0 <= I21 - 1 /\ 1 <= I20 - 1 /\ 0 <= I19 - 1 /\ I22 + 2 <= I20 /\ I22 + 1 <= I19 /\ I21 + 1 <= I20 /\ I21 <= I19] f3(I23, I24) -> f2(I25, I26) [-1 <= I26 - 1 /\ 0 <= I25 - 1 /\ 0 <= I23 - 1 /\ I25 <= I23] f1(I27, I28) -> f2(I29, I30) [-1 <= I30 - 1 /\ 0 <= I29 - 1 /\ -1 <= I28 - 1 /\ 0 <= I27 - 1 /\ I30 <= I28 /\ I29 - 1 <= I28 /\ I29 <= I27] popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to Integ Trans Syste 27634