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Integ Trans Syste 27634 pair #381739124
details
property
value
status
complete
benchmark
narrowKonv_rec.jar-obl-8.smt2
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n034.star.cs.uiowa.edu
space
From_AProVE_2014
run statistics
property
value
solver
Ctrl
configuration
Transition
runtime (wallclock)
0.488265037537 seconds
cpu usage
0.480453314
max memory
1.0612736E7
stage attributes
key
value
output-size
1868
starexec-result
MAYBE
output
/export/starexec/sandbox/solver/bin/starexec_run_Transition /export/starexec/sandbox/benchmark/theBenchmark.smt2 /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- MAYBE DP problem for innermost termination. P = init#(x1, x2) -> f1#(rnd1, rnd2) f2#(I0, I1) -> f2#(1, I1) [0 = I0 /\ 0 <= I1 - 1] f2#(I2, I3) -> f2#(0, I2 - 1) [I2 = I3 /\ 0 <= I2 - 1] f2#(I4, I5) -> f2#(I4 + 1, I5) [0 <= I4 - 1 /\ 0 <= I5 - 1 /\ I4 <= I5 - 1] f2#(I6, I7) -> f2#(0, 0) [0 = I7 /\ 0 = I6] f1#(I8, I9) -> f2#(I9, 20) [-1 <= I9 - 1 /\ 0 <= I8 - 1] R = init(x1, x2) -> f1(rnd1, rnd2) f2(I0, I1) -> f2(1, I1) [0 = I0 /\ 0 <= I1 - 1] f2(I2, I3) -> f2(0, I2 - 1) [I2 = I3 /\ 0 <= I2 - 1] f2(I4, I5) -> f2(I4 + 1, I5) [0 <= I4 - 1 /\ 0 <= I5 - 1 /\ I4 <= I5 - 1] f2(I6, I7) -> f2(0, 0) [0 = I7 /\ 0 = I6] f1(I8, I9) -> f2(I9, 20) [-1 <= I9 - 1 /\ 0 <= I8 - 1] The dependency graph for this problem is: 0 -> 5 1 -> 2, 3 2 -> 1, 4 3 -> 2, 3 4 -> 4 5 -> 1, 2, 3 Where: 0) init#(x1, x2) -> f1#(rnd1, rnd2) 1) f2#(I0, I1) -> f2#(1, I1) [0 = I0 /\ 0 <= I1 - 1] 2) f2#(I2, I3) -> f2#(0, I2 - 1) [I2 = I3 /\ 0 <= I2 - 1] 3) f2#(I4, I5) -> f2#(I4 + 1, I5) [0 <= I4 - 1 /\ 0 <= I5 - 1 /\ I4 <= I5 - 1] 4) f2#(I6, I7) -> f2#(0, 0) [0 = I7 /\ 0 = I6] 5) f1#(I8, I9) -> f2#(I9, 20) [-1 <= I9 - 1 /\ 0 <= I8 - 1] We have the following SCCs. { 1, 2, 3 } { 4 } DP problem for innermost termination. P = f2#(I6, I7) -> f2#(0, 0) [0 = I7 /\ 0 = I6] R = init(x1, x2) -> f1(rnd1, rnd2) f2(I0, I1) -> f2(1, I1) [0 = I0 /\ 0 <= I1 - 1] f2(I2, I3) -> f2(0, I2 - 1) [I2 = I3 /\ 0 <= I2 - 1] f2(I4, I5) -> f2(I4 + 1, I5) [0 <= I4 - 1 /\ 0 <= I5 - 1 /\ I4 <= I5 - 1] f2(I6, I7) -> f2(0, 0) [0 = I7 /\ 0 = I6] f1(I8, I9) -> f2(I9, 20) [-1 <= I9 - 1 /\ 0 <= I8 - 1]
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